如何解析文件以返回没有数字的大写行列表？ [关闭]

Question

这是我的输入文件：

THIS IS A TITLE

1. THIS IS A SUBTITLE

This is body text.
This is body text.

This is body text.
This is body text.

THIS IS A TITLE

This is body text.

THIS IS A TITLE

1. THIS IS A SUBTITLE

2. THIS IS A SUBTITLE

This is body text.
This is body text.

我想创建一个只有标题的列表，但不是字幕或正文。我怎么做？到目前为止，我想过循环遍历文件，抓住线条，如果它isupper()，但也抓住字幕。 isalpha()拒绝任何带有空格的标题，因此不起作用。我能做什么？我更喜欢循环而不是正则表达式。

Answer 1

在您阅读文件后，这是一个单行内容：

INPUT（如果读为一个字符串）：

output = [t for t in [i for i in s.split('\n') if all(j.isupper() for j in i.split())] if t!='']

INPUT（如果作为具有单独行的文件读取）：

output = [t for t in [i for i in lines if all(j.isupper() for j in i.split())] if t!='']

OUTPUT：

['THIS IS A TITLE', 'THIS IS A TITLE', 'THIS IS A TITLE']

Answer 2

没有正则表达式，你可以这样做：

# Read the file in as a single string, with all the newlines intact.
with open('file.txt', 'r') as f:
    file_str = f.read()

# Split into paragraphs
paragraphs = file_str.split('\n\n')

titles = []
for p in paragraphs:
    # Split a paragraph into lines, and get the first line of the paragraph
    # (which is the title).
    titles.append(p.split('\n')[0])

如果您将问题中提供的样本输入放入file.txt，变量titles将最终得到：

['THIS IS A TITLE', 'THIS IS A TITLE', 'THIS IS A TITLE']

Answer 3

您可以逐行读取文件到列表中，然后使用正则表达式：

import re
data = filter(None, [i.strip('\n') for i in open('filename.txt')])
new_data = [i for i in data if re.findall('^[A-Z\s]+$', i)]

输出：

['THIS IS A TITLE', 'THIS IS A TITLE', 'THIS IS A TITLE']