我想从系统表创建视图

Question

我想从系统表创建一个视图，我可以输出我想要运行的语法，但如何运行该输出命令？ 我创建了以下查询，它输出创建表的语法

SELECT

'CREATE VIEW [Uti_John].[Vw_' + x.table_name +']' +
' AS SELECT * FROM [' + x.schema_name + '].[' + x.table_name +']' 
FROM
(
SELECT SCHEMA_NAME(schema_id) AS schema_name  
       ,name AS table_name   
FROM sys.tables 
WHERE name like 'T%' 
and SCHEMA_NAME(schema_id) = 'dbo'
) x

输出

CREATE VIEW [Uti_John].[Vw_TNAME] AS SELECT * FROM [dbo].[TNAME]
CREATE VIEW [Uti_John].[Vw_TClient] AS SELECT * FROM [dbo].[TClient]
CREATE VIEW [Uti_John].[Vw_TClaim] AS SELECT * FROM [dbo].[TTClaim]
CREATE VIEW [Uti_John].[Vw_TInsurance] AS SELECT * FROM [dbo].[TTInsurance]
CREATE VIEW [Uti_John].[Vw_Ttest] AS SELECT * FROM [dbo].[Ttest]

手动一一复制此输出会创建视图，但我如何在循环中运行此输出并自动创建？

Answer 1

您可以使用

sys.views

视图来检查视图是否已存在。

DECLARE  @SQL NVARCHAR(max)='*';

WHILE @SQL IS NOT NULL
BEGIN 

    SET @SQL = NULL;

    SELECT @SQL = 
    'CREATE VIEW [Uti_John].[Vw_' + x.table_name +']' +
    ' AS SELECT * FROM [' + x.schema_name + '].[' + x.table_name +']' 
    FROM
    (
        SELECT SCHEMA_NAME(schema_id) AS schema_name  
               ,t.name AS table_name   
        FROM sys.tables t
        WHERE t.name like 't%' 
        and SCHEMA_NAME(t.schema_id) = 'dbo'
        AND NOT EXISTS (    SELECT * 
                            FROM sys.views v 
                            WHERE v.name = 'Vw_' + t.name 
                            AND OBJECT_SCHEMA_NAME(v.object_id) = 'Uti_John'
                        )
    ) x

    EXEC sp_executesql @SQL;

    PRINT @SQL;

END ;

Answer 2

如果表中有外键怎么办？