我有一个单词=“CAT”我有26个字母预制件A - Z - 预制阵列我想从预制件随机实例化6个预制件,所以B,L,T,C,A,T - 任何随机顺序,但我需要它包括构成单词cat的字母
我的第一个想法是使用字典/ hashmap将单词cat映射到数组中的位置,即C = [2] A = [0] T []但是hashmap / dictionary仅采用键值对但我提供它有多个值,需要3个字母
这是统一编程所以我的预制件已经在字母数组中,它只是让它们包括我的拼写。
public GameObject[] letters;
void Start() {
int x;
/* for loop execution */
for (x = 0; x < 5; x = x + 1)
{
CreateCubes();
}
}
public void CreateCubes()
{
GameObject obj = Instantiate(letters[Random.Range(0, 26)]);
obj.transform.position = new Vector3(
);
假设你有一个GameObject[]
数组中的所有预制件你可以使用它来自动填充字典
public GameObject[] prefabs = new GameObject[26];
private Dictionary<char, GameObject> CharToPrefab = new Dictionary<char, GameObject>(26);
private void Start()
{
for (var i = 0; i < 27; i++)
{
// add 0 to 26 to the start character A
// results in A-Z
CharToPrefab[(char)('A' + i)] = prefabs[i];
}
}
比你可以通过电话访问某个预制件
CharToPrefab[character];
为了生成实例(最简单的版本而不考虑任何双打),你可以做到例如
public void RandomLetters(string word)
{
// 1. spawn the minimum required letters to build the word
foreach (var letter in word)
{
var obj = Instantiate(CharToPrefab[letter]);
// maybe use obj for something e.g. shuffel all instantiated objects positions
}
// 2. fill the rest with random letters
// assuming always same amount as word letters
var rand = new System.Random();
foreach (var letter in word)
{
// pics a number from 0 to 26
// and adds it to the char -> results in A-Z
var randomChar = (char)('A' + rand.Next(0, 27));
var obj = Instantiate(CharToPrefab[randomChar]);
// maybe use obj for something e.g. shuffel all instantiated objects positions
}
}