我尝试用Arduino读取Adafruit INA 219传感器的电压和电流,我得到了正确的结果。问题是我需要分析这些结果,我需要在LabVIEW中读取传感器的值,或者将结果从Arduino发送到Labview中。
Arduino的代码。
#include <Wire.h>
#include <Adafruit_INA219.h>
Adafruit_INA219 ina219;
void setup(void)
{
Serial.begin(115200);
while (!Serial) {
// will pause Zero, Leonardo, etc until serial console opens
delay(1);
}
uint32_t currentFrequency;
Serial.println("Hello!");
// Initialize the INA219.
// By default the initialization will use the largest range (32V, 2A). However
// you can call a setCalibration function to change this range (see comments).
ina219.begin();
// To use a slightly lower 32V, 1A range (higher precision on amps):
//ina219.setCalibration_32V_1A();
// Or to use a lower 16V, 400mA range (higher precision on volts and amps):
//ina219.setCalibration_16V_400mA();
Serial.println("Measuring voltage and current with INA219 ...");
}
void loop(void)
{
float shuntvoltage = 0;
float busvoltage = 0;
float current_mA = 0;
float loadvoltage = 0;
shuntvoltage = ina219.getShuntVoltage_mV();
busvoltage = ina219.getBusVoltage_V();
current_mA = ina219.getCurrent_mA();
loadvoltage = busvoltage + (shuntvoltage / 1000);
Serial.print("Bus Voltage: "); Serial.print(busvoltage); Serial.println(" V");
//Serial.print("Shunt Voltage: "); Serial.print(shuntvoltage); Serial.println(" mV");
Serial.print("Load Voltage: "); Serial.print(loadvoltage); Serial.println(" V");
Serial.print("Current: "); Serial.print(current_mA); Serial.println(" mA");
Serial.println("");
delay(500);
}