MySQL 历史显示很多

Question

当我尝试查看 mysql 的历史记录时 - 我看到了这个

cat ~/.mysql_history

我明白了：

└──  cat ~/.mysql_history
_HiStOrY_V2_
exit
GRANT\040ALL\040PRIVILEGES\040ON\040*\040.\040*\040TO\040'jada'@'localhost';
FLUSH\040PRIVILEGES;
select\040User,Host\040from\040mysql.user;
exit
select\040User,Host\040from\040mysql.user;
GRANT\040ALL\040PRIVILEGES\040ON\040*\040.\040*\040TO\040'jada'@'localhost';
FLUSH\040PRIVILEGES;
select\040User,Host\040from\040mysql.user;
exit
drop\040database\app;\040
show\040databases;\040
create\040database\app;\040
exit
show\040databases;\040
use\app;\040
select\040*\040from\040users;\040
exit
use\app;\040
select\040*\040from\040users;\040
exit
select\040User,Host\040from\040mysql.user;
GRANT\040ALL\040PRIVILEGES\040ON\040*\040.\040*\040TO\040'jada'@'localhost';
FLUSH\040PRIVILEGES;
select\040User,Host\040from\040mysql.user;
exit
select\040User,Host\040from\040mysql.user;
exit
select\040*\040from\040users;
show\040databases;\040
use\app\040;\040
select\040*\040from\040users;
DELETE\040FROM\040table_name\040WHERE\040condition;
DELETE\040FROM\040users\040WHERE\040id\040=\0402;
select\040*\040from\040users;
history
show\040history;
exit

我看到了一堆

\040

。

如何在 bash 中看到像常规历史记录一样的干净历史记录？

我已经在 5 个虚拟机上尝试过。相同的结果。一直以来。

Answer 1

我记得mysql客户端上有一个老bug https://bugs.mysql.com/bug.php?id=68925 尝试更新一下

Answer 2

sed 's/\\040/ /g' < .mysql_history

这仅修复空格；我不知道问题的严重程度。

\0xx

是八进制转义序列。

40

是

space

的八进制。

Answer 3

这是perl的常见工作：

perl -pe 's/\\([0-7]{1,3})/chr oct $1/eg' <.mysql_history

这将解决八进制表示（不仅仅是空格）。

演示/测试：

perl -pe 's/\\([0-7]{1,3})/chr oct $1/eg' <<<"SELECT\040\042String\042;"
SELECT "String";

但这可以在shell

下完成

逐行，大多数情况下如果需要一行，你可以

echo -e "GRANT\040ALL\040PRIVILEGES\040ON\040*\040.\040*\040TO\040'jada'@'localhost';"
GRANT ALL PRIVILEGES ON * . * TO 'jada'@'localhost';

或者更好，使用 bash:

printf %b\\n "GRANT\040ALL\040PRIVILEGES\040ON\040*\040.\040*\040TO\040'jada'@'localhost';"
GRANT ALL PRIVILEGES ON * . * TO 'jada'@'localhost';

当然，您可以循环整个文件：

while read -r line ;do
    printf '%b\n' "$line"
done <.mysql_history

通过使用 sed彻底

地做到这一点

你必须运行

sed

两次：

sed "$(sed 's/\\\([0-9]\{3\}\)/\\o\1/g;s/^/1a\\/')" <<<''

对于标准输入或

sed "$(sed 's/\\\([0-9]\{3\}\)/\\o\1/g;s/^/1a\\/' .mysql_history)" <<<''

Answer 4

您可以简单地使用 sed 命令替换空格字符并为其定义一个别名，这样您就可以简单地调用 alias 而不是重复完整的命令：Alias mysqlh for mysql History

$ alias mysqlh="cat ~/.mysql_history | sed 's/\\\040/ /g'"
$ mysqlh
_HiStOrY_V2_
exit
GRANT ALL PRIVILEGES ON * . * TO 'jada'@'localhost';
FLUSH PRIVILEGES;
select User,Host from mysql.user;
exit
select User,Host from mysql.user;
GRANT ALL PRIVILEGES ON * . * TO 'jada'@'localhost';
FLUSH PRIVILEGES;
select User,Host from mysql.user;
exit
drop database\app;
show databases;
create database\app;
exit
show databases;
use\app;
select * from users;
exit
use\app;
select * from users;
exit
select User,Host from mysql.user;
GRANT ALL PRIVILEGES ON * . * TO 'jada'@'localhost';
FLUSH PRIVILEGES;
select User,Host from mysql.user;
exit
select User,Host from mysql.user;
exit
select * from users;
show databases;
use\app ;
select * from users;
DELETE FROM table_name WHERE condition;
DELETE FROM users WHERE id = 2;
select * from users;
history
show history;
exit