使用从 Google 表格中的单元格检索的资源名称从 Google 通讯录中删除联系人/人员

Question

GOAL: 
What i want to achieve is that i can pick in a list of resourceNames a specific resourceName and when i run the function in the (special) menu of my GoogleSheet, the selected resourceName is used to delete the person in the Google Contacts

person in googlesheet

我已在代码编辑器中激活 Peopleapi 作为服务。

当我运行该函数时，我收到此消息：“具有资源名称“xxx”的人不存在于“

我写了这些函数，我希望具有相应resourceName的人将从GoogleContacts中删除。

`function deletePerson() {
  var sheet = SpreadsheetApp.getActiveSpreadsheet().getActiveSheet();
  var resourceNameColumn = 1;  // Column A
  var resourceNameRow = 2;     // Start row 2

  // get the resourceName form the cell in the sheet
  var resourceName = sheet.getRange(resourceNameRow, resourceNameColumn).getValue();
  // var resourceName = "person/c4736325340303186435"
  //"person/c4736325340303186435";

  // Search for the person with the given resourceName in the People API
  var contactPerson = searchContactPerson(resourceName);

  if (contactPerson) {
    // if the person is found, get the unstructuredName en delete the person 
    var unstructuredName = contactPerson.names[0].unstructuredName;
    deleteContactPersoon(contactPerson.resourceName);
    
    // Give a message to the user that the person is deleted
    Browser.msgBox('Succes', 'Person with unstructuredName "' + unstructuredName + '" is deleted.', Browser.Buttons.OK);
  } else {
    // Giver a message to the user if the person is not found
    Browser.msgBox('Not Okay', 'Person with the resourceName "' + resourceName + '" does not exists als contactperson.', Browser.Buttons.OK);
  }
}

// Function to find the contactperson by means of the resourceName
function searchContactPerson(resourceName) {
//  var contacten = People.People.Connections.list('people/me').connections;
  var contacts = People.People.Connections.list('people/me', {
      //personFields: 'names,emailAddresses,addresses,resourceName,birthdays,phoneNumbers,urls,organizations,biographies'
      personFields: 'names'});
  for (var i = 0; i < contacts.length; i++) {
    if (contacts[i].resourceName == resourceName) {
      return contacts[i];
    }
  }
  return null; // Return null if person is not found
}

// Function to delete the contactperson by means of the resourceName
function deleteContactPerson(resourceName) {
  People.People.Connections.deleteContact(resourceName);
}`

Answer 1

修改要点：

• 在“方法：people.connections.list”的情况下，

  resourceName

  的属性位于数组

  connections

  中。因此，在这种情况下，您的函数

  searchContactPerson

  需要如下所示。我猜你的第一个问题的原因就是这个。

  function searchContactPerson(resourceName) {
    var contacts = People.People.Connections.list('people/me', { personFields: 'names' });
    for (var i = 0; i < contacts.connections.length; i++) {
      if (contacts.connections[i].resourceName == resourceName) {
        return contacts.connections[i];
      }
    }
    return null;
  }
  

• 在您的显示脚本中，未声明

  deleteContactPersoon

  的

  deleteContactPersoon(contactPerson.resourceName)

  。因此，当您的脚本运行时，该行会发生错误。我认为这是你的第二个问题。

• 要删除联系人，需要将

  People.People.Connections.deleteContact(resourceName)

  修改为

  People.People.deleteContact(resourceName);

  。我认为这是你的第三个问题。

• 为了使用

  resourceName

  搜索联系人，我认为可以使用“方法：people.getBatchGet”。在这种情况下，不需要使用循环。

修改后的脚本1：

当你的显示脚本修改后，它会变成如下。

function deletePerson() {
  var sheet = SpreadsheetApp.getActiveSpreadsheet().getActiveSheet();
  var resourceNameColumn = 1;  // Column A
  var resourceNameRow = 2;     // Start row 2

  // get the resourceName form the cell in the sheet
  var resourceName = sheet.getRange(resourceNameRow, resourceNameColumn).getValue();

  // Search for the person with the given resourceName in the People API
  var contactPerson = searchContactPerson(resourceName);
  if (contactPerson) {
    // if the person is found, get the unstructuredName en delete the person 
    var unstructuredName = contactPerson.names[0].unstructuredName;
    deleteContactPerson(contactPerson.resourceName);

    // Give a message to the user that the person is deleted
    Browser.msgBox('Succes', 'Person with unstructuredName "' + unstructuredName + '" is deleted.', Browser.Buttons.OK);
  } else {
    // Giver a message to the user if the person is not found
    Browser.msgBox('Not Okay', 'Person with the resourceName "' + resourceName + '" does not exists als contactperson.', Browser.Buttons.OK);
  }
}

// Function to find the contactperson by means of the resourceName
function searchContactPerson(resourceName) {
  var contacts = People.People.Connections.list('people/me', { personFields: 'names' });
  for (var i = 0; i < contacts.connections.length; i++) {
    if (contacts.connections[i].resourceName == resourceName) {
      return contacts.connections[i];
    }
  }
  return null;
}

// Function to delete the contactperson by means of the resourceName
function deleteContactPerson(resourceName) {
  People.People.deleteContact(resourceName);
}

• 运行此脚本时，当

  resourceName

  存在时，

  resourceName

  的联系人将被删除。请注意这一点。

修改后的脚本2：

作为另一种方法，当使用

resourceName

搜索联系人的方法发生变化时，就会变成如下。

function deletePerson() {
  var sheet = SpreadsheetApp.getActiveSpreadsheet().getActiveSheet();
  var resourceNameColumn = 1;  // Column A
  var resourceNameRow = 2;     // Start row 2
  var resourceName = sheet.getRange(resourceNameRow, resourceNameColumn).getValue();
  var contactPerson = searchContactPerson(resourceName);
  if (contactPerson) {
    deleteContactPerson(resourceName);
    Browser.msgBox('Succes', 'Person with unstructuredName "' + contactPerson + '" is deleted.', Browser.Buttons.OK);
  } else {
    Browser.msgBox('Not Okay', 'Person with the resourceName "' + resourceName + '" does not exists als contactperson.', Browser.Buttons.OK);
  }
}

function searchContactPerson(resourceName) {
  var res = People.People.getBatchGet({ personFields: "names", resourceNames: [resourceName] }).responses[0];
  return res.httpStatusCode == 200 ? res.person?.names[0]?.unstructuredName : false;
}

function deleteContactPerson(resourceName) {
  People.People.deleteContact(resourceName);
}

参考资料：

• 方法：people.connections.list
• 方法：people.getBatchGet