我有一个问题,将数组拆分为单独的数组奇数和偶数。我做的是:
componentDidMount() {
axios.get( `${this.props.cmsUrl}types/genres`)
.then(response => { if ( response.data !== undefined ) {
let even = [];
let odd = [];
let allData = ["a", "b", "c", "d", "e", "f", "g", "h", ];
for (var i = 0; i < allData.length; ++i) {
if ( ( allData[i] % 2 ) === 0) {
even.push(allData[i]);
}
else {
odd.push(allData[i]);
}
};
console.log("allData : ",allData);
console.log("even : ",even);
console.log("even : ",odd);
}}
)
}
我真正期待的是
allData = [a, b, c, d]
odd = [a , c]
even = [b, d]
但真正发生的是
allData = even
odd = empty array
这是我的问题=> ( allData[i] % 2 ) === 1
console.log是:
allData : (8) ["a", "b", "c", "d", "e", "f", "g", "h"]0: "a"1: "b"2: "c"3:
"d"4: "e"5: "f"6: "g"7: "h"length: 8__proto__: Array(0)
details.js:56 even : []length: 0__proto__: Array(0)
details.js:57 odd : (8) ["a", "b", "c", "d", "e", "f", "g", "h"]0:
"a"1: "b"2: "c"3: "d"4: "e"5: "f"6: "g"7: "h"length: 8__proto__: Array(0)
谢谢
您必须使用charCodeAt方法,因为allData是一个字符串数组而不是数字数组。
这是你的问题的解决方案:
if ( ( allData[i].charCodeAt(0) % 2 ) === 0) { your code }
=================
正如Thomas Scheffer所提到的那样,你似乎想要根据角色指数进行排序而不是它的价值。
所以如果你想根据索引排序你必须写:
if ( ( i % 2 ) === 0) { your code }
它像这样转换:
allData = ["b","f","z","w"] => { odd=["f","w"], even=["b","z"] }
但如果你想根据字符值排序,你必须写:
if ( ( allData[i].charCodeAt(0) % 2 ) === 0) { your code }
它像这样转换:
allData = ["b","f","z","w"] => { odd=["w"] , even=["b","f","z"] }
正确的条件是if ( ( allData[i] % 2 ) === 0)
试试控制台:
4 % 2
4 % 3
你可以使用Array.prototype.reduce
let allData = [ "a", "b", "c", "d", "e", "f", "g", "h" ];
const { even, odd } = allData.reduce((acc, val, index) => {
const key = index % 2 ? 'odd' : 'even';
return {
...acc,
[key]: acc[key].concat(val),
};
}, { odd: [], even: [] });
console.log( 'even', even );
console.log( 'odd', odd );
而不是for循环,你可以使用filter方法
/*ES6*/
let evenArray = result.filter((a,i) => i%2);
let oddArray = result.filter((a,i) => !(i%2));
/*ES5*/
let evenArray = result.filter(function(a,i){return i%2});
let oddArray = result.filter(function(a,i){return !(i%2)});