有没有一种方法可以设置对哈希值的期望，但对键是符号还是字符串“不关心”？

Question

使用 rspec-expectations 3.13.3 并具有如下代码：

def methname(**kwargs)
  # let's assume this method doesn't mind whether the kwargs are keyed by symbols or strings
  p(received: kwargs)
end

进行如下测试：

expect(something).to receive(:methname).with(hash_including(what_ever: "else"))

但在某些情况下，关键字参数被创建为字符串，而不是符号，因此失败，我必须这样做

expect(something).to receive(:methname).with(hash_including("what_ever" => "else"))

我可以在每个规范中做到这一点，但如果我能无差别地匹配它，对我来说会更干净 -

# desired code
expect(something).to receive(:methname).with(hash_including_indifferently(what_ever: "else"))

有办法做到这一点吗？

Answer 1

要明确的是，方法签名

def methname(**kwargs)

不能接受

Hash

的

{"what_ever => "else"}

，但我认为你的意思是：

def methname(h = {})
  p(received: h)
end

如果您想以允许

h

包含

{"what_ever" => "else"}

或

{what_ever: "else"}

的方式进行测试，您可以按如下方式进行测试：

expect(something).to receive(:methname) do |h| 
  expect(h).to  include(what_ever: "else").or include("what_ever" => "else")
end

因为带有块的

receive

会产生块的参数，并且您可以在使用 Compound Expectation 时显式测试它们。

话虽如此，鉴于访问的目的是“无关紧要”，您可能需要测试为：

RSpec::Matchers.define_negated_matcher :not_include, :include

 expect(something).to receive(:methname) do |h| 
      expect(h).to  include("what_ever").and(
                      not_include(:what_ever)
                    ).or(
                      include(:what_ever).and(
                         not_include("what_ever")
                      )
                    ).and( 
                       include({"what_ever" => "else"}).or(
                        include({what_ever: "else"})
                       )
                   )
    end

这将防止

Hash

同时包含

"what_ever"

和

:what_ever

键，同时确保其中一个键存在且值为

"else"

。