如何从Python中删除列表中的日期

Question

我有一个标记化文本列表（list_of_words），看起来像这样：

list_of_words = 
['08/20/2014',
 '10:04:27',
 'pm',
 'complet',
 'vendor',
 'per',
 'mfg/recommend',
 '08/20/2014',
 '10:04:27',
 'pm',
 'complet',
 ...]

我试图从这个列表中删除所有日期和时间的实例。我尝试过使用.remove（）函数无济于事。我已经尝试将通配符（例如'.. / .. / ....）传递给我正在排序的停用词列表，但这不起作用。我终于尝试编写以下代码：

for line in list_of_words:
    if re.search('[0-9]{2}/[09]{2}/[0-9]{4}',line):
        list_of_words.remove(line)

但这也不起作用。如何从列表中删除格式化为日期或时间的所有内容？

Answer 1

Description

^(?:(?:[0-9]{2}[:\/,]){2}[0-9]{2,4}|am|pm)$

这个正则表达式将执行以下操作：

• 找到看起来像日期12/23/2016和时间12:34:56的字符串
• 找到也是am或pm的字符串，它们可能是源列表中前一次的一部分

Example

现场演示

• 正则表达式：https://regex101.com/r/yE8oB9/2
• Python：http://codepad.org/X9D3pd7s

样品清单

08/20/2014
10:04:27
pm
complete
vendor
per
mfg/recommend
08/20/2014
10:04:27
pm
complete

处理后列表

complete
vendor
per
mfg/recommend
complete

示例Python脚本

import re

SourceList = ['08/20/2014',
                 '10:04:27',
                 'pm',
                 'complete',
                 'vendor',
                 'per',
                 'mfg/recommend',
                 '08/20/2014',
                 '10:04:27',
                 'pm', 
                 'complete']

OutputList = filter(
    lambda ThisWord: not re.match('^(?:(?:[0-9]{2}[:\/,]){2}[0-9]{2,4}|am|pm)$', ThisWord),
    SourceList)


for ThisValue in OutputList:
  print ThisValue

Explanation

NODE                     EXPLANATION
----------------------------------------------------------------------
  ^                        the beginning of the string
----------------------------------------------------------------------
  (?:                      group, but do not capture:
----------------------------------------------------------------------
    (?:                      group, but do not capture (2 times):
----------------------------------------------------------------------
      [0-9]{2}                 any character of: '0' to '9' (2 times)
----------------------------------------------------------------------
      [:\/,]                   any character of: ':', '\/', ','
----------------------------------------------------------------------
    ){2}                     end of grouping
----------------------------------------------------------------------
    [0-9]{2,4}               any character of: '0' to '9' (between 2
                             and 4 times (matching the most amount
                             possible))
----------------------------------------------------------------------
   |                        OR
----------------------------------------------------------------------
    am                       'am'
----------------------------------------------------------------------
   |                        OR
----------------------------------------------------------------------
    pm                       'pm'
----------------------------------------------------------------------
  )                        end of grouping
----------------------------------------------------------------------
  $                        before an optional \n, and the end of the
                           string
----------------------------------------------------------------------

Answer 2

如果你想要数学列表中的时间和日期字符串，也许你可以尝试下面的正则表达式：

[0-9]{2}[\/,:][0-9]{2}[\/,:][0-9]{2,4}

添加python代码：

import re

list_of_words = [
 '08/20/2014',
 '10:04:27',
 'pm',
 'complet',
 'vendor',
 'per',
 'mfg/recommend',
 '08/20/2014',
 '10:04:27',
 'pm',
 'complet'
]
new_list = [item for item in list_of_words if not re.search(r'[0-9]{2}[\/,:][0-9]{2}[\/,:][0-9]{2,4}', item)]

Answer 3

试试这个：

import re

list_of_words = ['08/20/2014',
                 '10:04:27',
                 'pm',
                 'complet',
                 'vendor',
                 'per',
                 'mfg/recommend',
                 '08/20/2014',
                 '10:04:27',
                 'pm', 'complet']

list_of_words = filter(
    lambda x: not re.match('[0-9]{2}[\/,:][0-9]{2}[\/,:][0-9]{2,4}', x),
    list_of_words)