Scrapy：如何从页面上的所有选项卡获取信息？

Question

在此page上，我需要从所有选项卡（配置文件，评论，电话号码和方向）获取信息。

wellness.py

def profile(self, response):
    services = response.xpath('.//span[contains(text(),"Services")]')
    education = response.xpath('.//span[contains(text(),"Education")]')
    training = response.xpath('.//span[contains(text(),"Training")]')

    yield {
            'First and Last name': response.css('h1::text').get(),
            'About': response.css('.listing-about::text').get(),
            'Services': services.xpath('following-sibling::span[1]/text()').extract(),
            'Primary Specialty': response.css('.normal::text').get(),
            'Address': ' '.join([i.strip() for i in response.css('.office-address span::text').getall()]),
            'Practice': response.css('.years-in-service::text').get(),
            'Education': education.xpath('following-sibling::span[1]/text()').extract(),
            'Training': training.xpath('following-sibling::span[1]/text()').extract(),
            'Consumer Feedback': response.css('.item-rating-container a::text').get()                
        }

Answer 1

每个选项卡正在加载单独的页面，因此您将必须从第一页收集想要的数据，请求第二页获取数据，然后请求第三页。这就是我要做的。请注意，链接代码正确无误，您必须在每个页面上为数据点选择器。

def profile(self, response):
    item["data1"] = response.xpath('//xpath').get()
    # Get first link for reviews
    review_link = response.css('#reviews_tab a::attr(href)').get()
    yield scrapy.Request(response.urljoin(review_link), callback=self.parse_reviews, meta={'item': item})

def parse_reviews(self, response):
    item = response.meta['item']
    item["review_data"] = response.xpath
    directions_link = response.css('#directions_tab a:attr(href)').get()
    yield scrapy.Request(response.urljoin(directions_link), callback=self.parse_directions, meta={'item': item})

def parse_directions(self, response):
    item = response.meta['item']
    item['directions'] = response.xpath
    yield item