如何根据某个值拆分数组？

问题描述 投票：0回答：3

我目前有一组类似于下面的基于位置的信息（已按时间排序）。第一个键/值是事件，代表旅程的开始 (00)、运行的旅程 (01) 和旅程的结束 (10)。

Array ( 
[0] => Array ( [event] => 00 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[1] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[2] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[3] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[4] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[5] => Array ( [event] => 10 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[6] => Array ( [event] => 00 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[7] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[8] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[9] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[10] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[11] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[12] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[13] => Array ( [event] => 10 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[14] => Array ( [event] => 00 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[15] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[16] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[17] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[18] => Array ( [event] => 10 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
)

如何进一步拆分数组，以便为每次旅程创建一个新数组，这样我最终会得到这样的结果：

Array (
[0] => Array (
[0] => Array ( [event] => 00 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[1] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[2] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[3] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[4] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[5] => Array ( [event] => 10 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
)
[1] => Array (
[0] => Array ( [event] => 00 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[1] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[2] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[3] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[4] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[5] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[6] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[7] => Array ( [event] => 10 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
)
...
)

我还没有尝试过任何东西（除了谷歌搜索），因为我真的不知道从哪里开始。

php arrays multidimensional-array
3个回答
2
投票

您需要像这样的自定义解决方案：

 $outputArray = array(); $currentArray = array();
 foreach($inputArray as $key=>$subArray) {
   if($subArray['event']==00) {
      $outputArray[] = $currentArray;
      $currentArray = array($subArray);
   } else {
      $currentArray[] = $subArray;
   }
 }
 $outputArray[] = $currentArray;
 array_shift($outputArray);

放入$inputArray，然后取出$outputArray。 享受吧！

1
投票

试试这个：

$journey = array ( 
[0] => Array ( [event] => 00 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[1] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[2] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[3] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[4] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[5] => Array ( [event] => 10 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[6] => Array ( [event] => 00 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[7] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[8] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[9] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[10] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[11] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[12] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[13] => Array ( [event] => 10 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[14] => Array ( [event] => 00 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[15] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[16] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[17] => Array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
[18] => Array ( [event] => 10 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 )
)

$journeygrouping = array();

while(!empty($journey)){
$temp = array_pop($journey);

if(isset($journeygrouping[$temp['event']])){
  array_push($journeygrouping[$temp['event']], $temp);
} else {
  $journeygrouping[$temp['event']] = array();
  array_push($journeygrouping[$temp['event']], $temp);
}
}

这段代码应该创建一个像这样的数组结构：

array(
[00] => array([0] => array([event] => 00 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111) [1]=>array ( [event] => 00 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111 ))
[01] => array([0]=>array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111) [1]=>array ( [event] => 01 [time] => 1329293878 [lat] => 66.66666 [lon] => 11.11111)  )
);

等等...

0
投票

对于将从空输入数组生成空结果数组的干净脚本，请避免在循环构造之外进行处理。 @hackartist 的答案将从空输入数组创建一个非空数组。为了避免改变输入数组，请勿通过调用 

array_pop()
来消耗元素，如 @Christopher Pelayo 的答案。

我建议仅当输入数组中有元素时才将引用变量推入结果数组，并将与集合相关的元素推入引用变量。 这样您就不需要跟踪结果数组中当前组的位置。

代码：（演示）

$result = [];
foreach ($array as $row) {
    if ($row['event'] === '00') {
        unset($ref);
        $result[] =& $ref;
    }
    $ref[] = $row;
}
var_export($result);
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