我如何访问使用get方法发送的参数？ [重复]

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How to use Servlets and Ajax?（7个答案）

关闭昨天。

我正在尝试将位置数据从javascript发送到我的servlet，并及时将其存储在数据库中。我一直不知道如何访问我的参数？]

NewFile.html

<script>
    $(document).on("click", "#somebutton", function() {
        if (navigator.geolocation) {

            navigator.geolocation.watchPosition(showPosition);
        } else {
            x.innerHTML = "Geolocation is not supported by this browser.";
        }

        function showPosition(position) {
            console.log(position)

            var params = {
                lat : position.coords.latitude,
                lng : position.coords.longittude
            };

            $.get("someservlet", $.param(params), function(responseText) { // Execute Ajax GET request on URL of "someservlet" and execute the following function with Ajax response text...
                // Locate HTML DOM element with ID "somediv" and set its text content with the response text.
            });

        }

    });
</script>
servlet.java

public class servlet extends HttpServlet {
    private static final long serialVersionUID = 1L;



    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        String text = "some text";
       String params= request.getParameter("params");
        System.out.println(params);
    }

}

我正在尝试将位置数据从javascript发送到我的servlet，并及时将其存储在数据库中。我一直不知道如何访问我的参数？ NewFile.html

您的Servlet：

public class servlet extends HttpServlet {
    private static final long serialVersionUID = 1L;


    @Override
    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        String text = "some text";
        System.out.println(String.format("Lat: %s Long: %s", request.getParameter("lat"), request.getParameter("lng")));
    }

}
我建议您关注naming conventions：

类名应为名词，每个内部单词的首字母应大写。尝试使您的类名称保持简单和描述性。使用整个单词，避免使用首字母缩写词和缩写词（除非缩写词比长格式（如URL或HTML）使用得更广泛）。

Answer 1

您的Servlet：