Hive按组计算中位数和平均值

Question

我有一个按州和县计数的数据集，我想按州和县计算中位数和平均值，例如：

有：

ID  state    county  count
1   MD       aa          2
2   MD       aa          4
3    VA        bb         1
4    VA        bb         2
5    VA        bb         4
6    VA        cc          7
7    VA        cc          8

想要：

到目前为止我给我的错误：

Select id,  STATE,COUNTY,count,
percentile(cast(count as BIGINT), 0.5) OVER() as overall_median, 
round(avg(count),2) OVER() as overall_avg,

percentile(cast(count as bigint),0.5) OVER(PARTITION BY id,STATE) as med_state,
percentile(cast(count as bigint),0.5) as med_county,

AVG(count) OVER (PARTITION BY id, STATE) as avg_state,
AVG(count) AS avg_county,
from have
group by id, state, county

不使用组时收到错误：

错误：执行错误：org.apache.hive.service.cli.HiveSQLException：编译语句时出错：FAILED：SemanticException无法将窗口调用分解为组。至少1组必须仅取决于输入列。同时检查循环依赖项。基本错误：org.apache.hadoop.hive.ql.parse.SemanticException：行1：457表达式不在GROUP BY键'id'

不带组的代码：

Select id,  STATE,county,count,
percentile(cast(count as BIGINT), 0.5) OVER() as overall_median, 
round(avg(count),2) OVER() as overall_avg,

percentile(cast(count as bigint),0.5) OVER(PARTITION BY id,STATE) as med_state,
percentile(cast(count as bigint),0.5) OVER(PARTITION BY id,STATE,county) as med_county,


AVG(count) OVER (PARTITION BY id, STATE) as avg_state,
AVG(count) OVER (PARTITION BY id, STATE, county) as avg_county,
from have

谢谢！

Answer 1

修复它：round（avg（count）OVER（），2）

    select 
        id, STATE, county, count,
        percentile(cast(count as BIGINT), 0.5) OVER() as overall_median, 
        round(avg(count) OVER(), 2) as overall_avg,

        percentile(cast(count as bigint), 0.5) OVER(PARTITION BY id, STATE) as med_state,
        percentile(cast(count as bigint), 0.5) OVER(PARTITION BY id, STATE, county) as med_county,

        AVG(count) OVER (PARTITION BY id, STATE) as avg_state,
        AVG(count) OVER (PARTITION BY id, STATE, county) as avg_county
    from 
        have

提示：请勿将关键字（即计数）用作列名-将来会遇到很多问题