合并两个XDocument

Question

我有两个xml，我必须合并一个特定的节点

这是第一个：

<ContactEmployees>
  <row>
    <Name>NAME</Name>
    <Position>Mag</Position>
    <Phone1>number</Phone1>
    <E_Mail>mail</E_Mail>
    <InternalCode>11</InternalCode>
    <Gender>gt_Undefined</Gender>
    <Active>tYES</Active>
    <FirstName>Tizio</FirstName>
    <BlockSendingMarketingContent>tNO</BlockSendingMarketingContent>
  </row>
</ContactEmployees>

这是第二个：

<ContactEmployees>
      <row>
        <CardCode>1000010</CardCode>
        <Name>NAME</Name>
        <Position>Mag</Position>
        <Phone1>number</Phone1>
        <E_Mail>mail</E_Mail>
        <InternalCode>11</InternalCode>
        <Gender>gt_Undefined</Gender>
        <Active>tYES</Active>
        <BlockSendingMarketingContent>tNO</BlockSendingMarketingContent>
      </row>
      <row>
        <CardCode>1000010</CardCode>
        <Name>Prova</Name>
        <InternalCode>2703</InternalCode>
        <PlaceOfBirth>-1</PlaceOfBirth>
        <Gender>gt_Undefined</Gender>
        <Active>tYES</Active>
        <FirstName>Prova</FirstName>
        <BlockSendingMarketingContent>tNO</BlockSendingMarketingContent>
      </row>
    </ContactEmployees>

这是合并后我期望的结果：

<ContactEmployees>
       <row>
        <Name>NAME</Name>
        <Position>Mag</Position>
        <Phone1>number</Phone1>
        <E_Mail>mail</E_Mail>
        <InternalCode>11</InternalCode>
        <Gender>gt_Undefined</Gender>
        <Active>tYES</Active>
        <FirstName>Tizio</FirstName>
        <BlockSendingMarketingContent>tNO</BlockSendingMarketingContent>
      </row>
      <row>
        <CardCode>1000010</CardCode>
        <Name>Prova</Name>
        <InternalCode>2703</InternalCode>
        <PlaceOfBirth>-1</PlaceOfBirth>
        <Gender>gt_Undefined</Gender>
        <Active>tYES</Active>
        <FirstName>Prova</FirstName>
        <BlockSendingMarketingContent>tNO</BlockSendingMarketingContent>
      </row>
    </ContactEmployees>

我尝试做IEnumerable<XElement> merge = xdoc.Root.Descendants("ContactEmployees").Concat("ContactEmployees")); xdoc是我的所有xml文档，其中“ContactEmployees”节点是其中的一部分，但是concat方法生成一个带有三个节点或队列所有节点的xml，我尝试了union但排除了第二个xml，我不明白我怎么能用查询试图查看InternalCode属性，因为我不能以任何方式修改它，所以它是唯一的？

-Edit-我回顾了一下情况，Internalcode可以是不同的（它们是数据库的数据）而Name可以修改它（Name，InternalCode和CardCode是我表的关键），所以我实际上必须合并同一行并从第二个xml添加新行，我不知道它有多可行

Answer 1

这是一个带有显式foreach循环的解决方案：

var doc = XDocument.Parse(@"<ContactEmployees>
  <row>
    <Name>NAME</Name>
    <Position>Mag</Position>
    <Phone1>number</Phone1>
    <E_Mail>mail</E_Mail>
    <InternalCode>11</InternalCode>
    <Gender>gt_Undefined</Gender>
    <Active>tYES</Active>
    <FirstName>Tizio</FirstName>
    <BlockSendingMarketingContent>tNO</BlockSendingMarketingContent>
  </row>
</ContactEmployees>");

var doc2 = XDocument.Parse(@"<ContactEmployees>
      <row>
        <CardCode>1000010</CardCode>
        <Name>NAME</Name>
        <Position>Mag</Position>
        <Phone1>number</Phone1>
        <E_Mail>mail</E_Mail>
        <InternalCode>11</InternalCode>
        <Gender>gt_Undefined</Gender>
        <Active>tYES</Active>
        <BlockSendingMarketingContent>tNO</BlockSendingMarketingContent>
      </row>
      <row>
        <CardCode>1000010</CardCode>
        <Name>Prova</Name>
        <InternalCode>2703</InternalCode>
        <PlaceOfBirth>-1</PlaceOfBirth>
        <Gender>gt_Undefined</Gender>
        <Active>tYES</Active>
        <FirstName>Prova</FirstName>
        <BlockSendingMarketingContent>tNO</BlockSendingMarketingContent>
      </row>
    </ContactEmployees>");

var employees = doc.Root;

var employees2 = doc2.Root;

foreach (var row2 in employees2.Elements("row"))
{
    // the following may be adapted to whatever criterion shall be used
    // to identify a record
    var id2 = row2.Element("InternalCode").Value;
    var row = employees.Elements("row").FirstOrDefault(r => r.Element("InternalCode").Value == id2);

    if (row == null)
    {
        // row not found in doc, so add it
        employees.Add(row2);
    }
    else
    {
        // row found; maybe update it, e.g.
        var nameElement2 = row2.Element("Name");
        if (nameElement2 != null)
        {
            var nameElement = row.Element("Name");
            if (nameElement == null)
                nameElement = nameElement2;
            else
                nameElement.Value = nameElement2.Value;
        }
    }
}

生成的XML位于doc中。