取决于某些条件/属性名称等的JsonView序列化

Question

我的一个班级有3个相同类型的属性。现在，我尝试将其序列化为JSON，但是其中一个属性需要以不同的方式序列化-基本上，这些属性之一是“内部”，我只需要它的ID，其余的必须完全序列化。

我到目前为止所到之处：

@NoArgsConstructor @AllArgsConstructor @Data
public static class Id {
    @JsonView(View.IdOnly.class) private long id;
}

@NoArgsConstructor @AllArgsConstructor @Data
public static class Company extends Id {
    @JsonView(View.Tx.class) private String name;
    @JsonView(View.Tx.class) private String address;
}

@NoArgsConstructor @AllArgsConstructor @Data
public static class Transaction {
    @JsonView(View.Tx.class)     private Company from;
    @JsonView(View.Tx.class)     private Company to;
    @JsonView(View.IdOnly.class) private Company createdBy;
}

public static class View {
    public interface Tx extends IdOnly {}
    public interface IdOnly {}
}

并对其进行快速测试：

@Test
void test() throws JsonProcessingException {
    Company s = new Company("Source", "address_from");
    Company d = new Company("Destination", "address_to");
    final Transaction t = new Transaction(s, d, s);

    final ObjectMapper m = new ObjectMapper();
    System.out.println(m.writerWithDefaultPrettyPrinter().withView(View.Tx.class).writeValueAsString(t));
}

输出为：

{
  "from" : {
    "id" : 0,
    "name" : "Source",
    "address" : "address_from"
  },
  "to" : {
    "id" : 0,
    "name" : "Destination",
    "address" : "address_to"
  },
  "createdBy" : {
    "id" : 0,
    "name" : "Source",
    "address" : "address_from"
  }
}

[现在，问题，如何自定义createBy属性的序列化？我需要以下输出：

{
  "from" : {
    "id" : 0,
    "name" : "Source",
    "address" : "address_from"
  },
  "to" : {
    "id" : 0,
    "name" : "Destination",
    "address" : "address_to"
  },
  "createdBy" : {
    "id" : 0,
  }
}

Answer 1

我认为我有解决方法。

首先，我在事务类中添加了getter，如下所示：

    public Company getCreatedBy() {
        return new Wrapper(createdBy);
    }

Wrapper类的内容是：

@JsonInclude(JsonInclude.Include.NON_NULL)
public static class Wrapper extends Company {
    private Company c;
    public Wrapper(Company c) { this.c = c; }

    @JsonIgnore public String getName() { return null; }
    @JsonIgnore public String getAddress() { return null; }

    @JsonView(View.IdOnly.class) public long getId() { return super.getId(); }
}

否，我只有createdBy属性的ID，而其他属性的完整数据。