DataSet中的多级xml并输出到dataGridView1表

Question

由于子表中的名称相同，DataSet 错误地将 XML 数据输出到 dataGridView1。

这是我的代码...

 DataSet dataSet = new DataSet("Language");

 private void button1_Click_1(object sender, EventArgs e)
 {
     OpenFileDialog ofd = new OpenFileDialog();
     ofd.Filter = "XML|*.xml";
     if (ofd.ShowDialog() == DialogResult.OK)
     {
         try
         {
             List<string> listTableName = new List<string>();
             XmlReader xmlFile = XmlReader.Create(ofd.FileName, new XmlReaderSettings());
             dataSet.ReadXml(xmlFile);

             for (int i = 0; i <= dataSet.Tables.Count - 1; i++)
                 if (dataSet.Tables[i].ChildRelations.Count != 0)
                     comboBox1.Items.Add(dataSet.Tables[i].TableName); 

             dataGridView1.DataSource = dataSet.Tables[0].DefaultView;
             xmlFile.Close();

         }

         catch (Exception ex)
         {
             Console.WriteLine(ex);
         }
     }
 }

 private void comboBox1_SelectedIndexChanged(object sender, EventArgs e)
 {
     if (comboBox1.SelectedIndex == 0)
         dataGridView1.DataSource = dataSet.Tables[comboBox1.SelectedIndex].DefaultView;
     else
         dataGridView1.DataSource = dataSet.Tables[comboBox1.Text].ChildRelations[0].ChildTable.DefaultView;
 }

这是 xml

<?xml version="1.0" encoding="utf-8"?>
<Language xmlns:dt="some-xml-namespace-here" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
  <Name>English</Name>
  <Code>EN</Code>
  <Font>font_english</Font>
  <Reagents>
    <RecordReagent>
      <Key>Flour</Key>
      <Value>Flour</Value>
      <Unit>g</Unit>
    </RecordReagent>
    <RecordReagent>
      <Key>Milk</Key>
      <Value>Milk</Value>
      <Unit>ml</Unit>
    </RecordReagent>
  </Reagents>
  <Gases>
    <Record>
      <Key>Oxygen</Key>
      <Value>Oxygen</Value>
    </Record>
    <Record>
      <Key>CarbonDioxide</Key>
      <Value>Carbon Dioxide</Value>
    </Record>
    <Record>
      <Key>Nitrogen</Key>
      <Value>Nitrogen</Value>
    </Record>
  </Gases>
  <Actions>
    <Record>
      <Key>Reload</Key>
      <Value>Reload</Value>
    </Record>
        <Record>
      <Key>123124</Key>
      <Value>1323123</Value>
    </Record>
  </Actions>
  <ScreenSpaceToolTips />
</Language>

问题是气体和动作表具有相同的记录表，而不是它们自己的。在俄罗斯论坛上，我没有收到有关如何制作的答案，因此在选择comboBox1 Gases时，会选择其记录表而不是通用表（而代码应该是通用的，无需指定表名称）

Answer 1

尝试使用 Xml Linq 执行以下代码

using System;
using System.Linq;
using System.Collections.Generic;
using System.Data;
using System.Xml;
using System.Xml.Linq;

namespace ConsoleApp10
{

    class Program
    {
        const string FILENAME = @"c:\temp\test.xml";
        static void Main(string[] args)
        {
            XDocument doc = XDocument.Load(FILENAME);

            DataSet language = new DataSet("Language");

            DataTable dt = new DataTable("Reagents");
            language.Tables.Add(dt);
            dt.Columns.Add("Key", typeof(string));
            dt.Columns.Add("Value", typeof(string));
            dt.Columns.Add("Unit", typeof(string));

            foreach (XElement reagents in doc.Descendants("RecordReagent"))
            {
                string key = (string)reagents.Element("Key");
                string value = (string)reagents.Element("Value");
                string unit = (string)reagents.Element("Unit");
                dt.Rows.Add(new  { key, value, unit });
            }

            XElement gases = doc.Descendants("Gases").FirstOrDefault();

            dt = new DataTable("Gases");
            language.Tables.Add(dt);
            dt.Columns.Add("Key", typeof(string));
            dt.Columns.Add("Value", typeof(string));

            foreach (XElement record in gases.Descendants("Record"))
            {
                string key = (string)record.Element("Key");
                string value = (string)record.Element("Value");
                dt.Rows.Add(new { key, value});
            }

            XElement actions = doc.Descendants("Actions").FirstOrDefault();

            dt = new DataTable("Actions");
            language.Tables.Add(dt);
            dt.Columns.Add("Key", typeof(string));
            dt.Columns.Add("Value", typeof(string));

            foreach (XElement record in actions.Descendants("Record"))
            {
                string key = (string)record.Element("Key");
                string value = (string)record.Element("Value");
                dt.Rows.Add(new { key, value });
            }

        }


    }

}