如何使所有字段具有以别名名的名称？

Question

创建我的模型可选。

I创建的功能以获取基类注释。

def get_annotations(main_cls):
    ret_val = main_cls.__annotations__
    for base_cls in main_cls.__bases__:
        if base_cls != BaseModel:
            ret_val.update(get_annotations(base_cls))
    return ret_val

创建可选模型AS

OptionalClientModel = create_model(
    "OptionalClientModel",
    **{k: (Optional[v], None) for k, v in get_annotations(ClientModel).items()})

原始课程如下

from typing import Annotated
from bson import ObjectId

from pydantic import Field
from pydantic import EmailStr
from pydantic import BaseModel
from pydantic import ConfigDict
from pydantic import AwareDatetime
from pydantic import field_validator

# Represents an ObjectId field in the database.
# It will be represented as a `str` on the model so that it can
# be serialized to JSON.
PyObjectId = Annotated[str, BeforeValidator(str)]

class DBTableBase(BaseModel):
    # The primary key for the Table, stored as a `str` on the instance.
    # This will be aliased to `_id` when sent to MongoDB,
    # but provided as `id` in the API requests and responses.
    id: PyObjectId | None = Field(alias="_id",
                                  serialization_alias="id",
                                  default=None)
    model_config = ConfigDict(
        json_encoders={ObjectId: str},
        json_schema_extra={
            "example": {
                "id": "BSON_ID"
            }
        },
    )

class ClientModel(DBTableBase):
    first_name: str
    last_name: str

当我想要具有所有可选值的型号时，我可以使用

OptionalClientModel

。

问题是，

id

没有任何Alia。

如何与别名创建可选？
    

OptionalClientModel

这应该满足您的需求。无需自己迭代注释。