令我惊讶的是，据我所知，在 .NET BCL 中我无法做任何像这样简单的事情：
byte[] response = Http.Post
(
url: "http://dork.com/service",
contentType: "application/x-www-form-urlencoded",
contentLength: 32,
content: "home=Cosby&favorite+flavor=flies"
);
上面的假设代码使用数据进行 HTTP POST，并从静态类
PostHttp既然我们没有这么简单的东西，那么下一个最佳解决方案是什么？
如何发送带有数据的 HTTP POST 并获取响应的内容？
using (WebClient client = new WebClient())
{
byte[] response =
client.UploadValues("http://dork.com/service", new NameValueCollection()
{
{ "home", "Cosby" },
{ "favorite+flavor", "flies" }
});
string result = System.Text.Encoding.UTF8.GetString(response);
}
您将需要这些包括：
using System;
using System.Collections.Specialized;
using System.Net;
如果您坚持使用静态方法/类：
public static class Http
{
public static byte[] Post(string uri, NameValueCollection pairs)
{
byte[] response = null;
using (WebClient client = new WebClient())
{
response = client.UploadValues(uri, pairs);
}
return response;
}
}
然后简单地说：
var response = Http.Post("http://dork.com/service", new NameValueCollection() {
{ "home", "Cosby" },
{ "favorite+flavor", "flies" }
});
使用 HttpClient：就 Windows 8 应用程序开发问题而言，我遇到过这一点。
var client = new HttpClient();
var pairs = new List<KeyValuePair<string, string>>
{
new KeyValuePair<string, string>("pqpUserName", "admin"),
new KeyValuePair<string, string>("password", "test@123")
};
var content = new FormUrlEncodedContent(pairs);
var response = client.PostAsync("youruri", content).Result;
if (response.IsSuccessStatusCode)
{
}
使用WebRequest。来自斯科特汉塞尔曼：
public static string HttpPost(string URI, string Parameters)
{
System.Net.WebRequest req = System.Net.WebRequest.Create(URI);
req.Proxy = new System.Net.WebProxy(ProxyString, true);
//Add these, as we're doing a POST
req.ContentType = "application/x-www-form-urlencoded";
req.Method = "POST";
//We need to count how many bytes we're sending.
//Post'ed Faked Forms should be name=value&
byte [] bytes = System.Text.Encoding.ASCII.GetBytes(Parameters);
req.ContentLength = bytes.Length;
System.IO.Stream os = req.GetRequestStream ();
os.Write (bytes, 0, bytes.Length); //Push it out there
os.Close ();
System.Net.WebResponse resp = req.GetResponse();
if (resp== null) return null;
System.IO.StreamReader sr =
new System.IO.StreamReader(resp.GetResponseStream());
return sr.ReadToEnd().Trim();
}
private void PostForm()
{
HttpWebRequest request = (HttpWebRequest)WebRequest.Create("http://dork.com/service");
request.Method = "POST";
request.ContentType = "application/x-www-form-urlencoded";
string postData ="home=Cosby&favorite+flavor=flies";
byte[] bytes = Encoding.UTF8.GetBytes(postData);
request.ContentLength = bytes.Length;
Stream requestStream = request.GetRequestStream();
requestStream.Write(bytes, 0, bytes.Length);
WebResponse response = request.GetResponse();
Stream stream = response.GetResponseStream();
StreamReader reader = new StreamReader(stream);
var result = reader.ReadToEnd();
stream.Dispose();
reader.Dispose();
}
就我个人而言，我认为执行 http post 并获取响应的最简单方法是使用 WebClient 类。这个类很好地抽象了细节。 MSDN 文档中甚至还有完整的代码示例。
http://msdn.microsoft.com/en-us/library/system.net.webclient(VS.80).aspx
在您的情况下，您需要 UploadData() 方法。 （同样，文档中包含代码示例）
http://msdn.microsoft.com/en-us/library/tdbbwh0a(VS.80).aspx
UploadString() 可能也能工作，并且它将它抽象了一层。
http://msdn.microsoft.com/en-us/library/system.net.webclient.uploadstring(VS.80).aspx
鉴于其他答案已有几年历史，目前以下是我的想法可能会有所帮助：
最简单的方法
private async Task<string> PostAsync(Uri uri, HttpContent dataOut)
{
var client = new HttpClient();
var response = await client.PostAsync(uri, dataOut);
return await response.Content.ReadAsStringAsync();
// For non strings you can use other Content.ReadAs...() method variations
}
更实际的例子
我们通常处理已知类型和 JSON，因此您可以通过任意数量的实现进一步扩展这个想法，例如：
public async Task<T> PostJsonAsync<T>(Uri uri, object dtoOut)
{
var content = new StringContent(JsonConvert.SerializeObject(dtoOut));
content.Headers.ContentType = MediaTypeHeaderValue.Parse("application/json");
var results = await PostAsync(uri, content); // from previous block of code
return JsonConvert.DeserializeObject<T>(results); // using Newtonsoft.Json
}
如何调用它的示例：
var dataToSendOutToApi = new MyDtoOut();
var uri = new Uri("https://example.com");
var dataFromApi = await PostJsonAsync<MyDtoIn>(uri, dataToSendOutToApi);
我知道这是一个旧线程，但希望它对某人有所帮助。
public static void SetRequest(string mXml)
{
HttpWebRequest webRequest = (HttpWebRequest)HttpWebRequest.CreateHttp("http://dork.com/service");
webRequest.Method = "POST";
webRequest.Headers["SOURCE"] = "WinApp";
// Decide your encoding here
//webRequest.ContentType = "application/x-www-form-urlencoded";
webRequest.ContentType = "text/xml; charset=utf-8";
// You should setContentLength
byte[] content = System.Text.Encoding.UTF8.GetBytes(mXml);
webRequest.ContentLength = content.Length;
var reqStream = await webRequest.GetRequestStreamAsync();
reqStream.Write(content, 0, content.Length);
var res = await httpRequest(webRequest);
}
您可以使用类似这样的伪代码：
request = System.Net.HttpWebRequest.Create(your url)
request.Method = WebRequestMethods.Http.Post
writer = New System.IO.StreamWriter(request.GetRequestStream())
writer.Write("your data")
writer.Close()
response = request.GetResponse()
reader = New System.IO.StreamReader(response.GetResponseStream())
responseText = reader.ReadToEnd
这是来自 .net 7 的示例：
请注意，httpClient.PostAsJsonAsync 是一个扩展方法。这意味着您必须将 System.Net.Http.Json 添加到您的项目中，然后使用它
using System.Text.Json;另请注意，此示例为每个请求实例化一个 httpClient。不建议这样做。这种做法会在每次调用时强制建立新的连接，这需要新的 https 握手。相反，请使用单例或静态实例。有关如何正确实现此功能的完整详细信息，请参阅文档，或在此处观看我的视频：https://youtu.be/BA1e_ez8fwI?si=Tt0ppiIxoVOX57mA
var roomRequest = new RoomRequest() { EndDate = DateTime.Now.AddHours(2) };
RoomRequestResponse roomRequestResponse;
var apiKey = await this.DataStore.GetAppSetting("whereby-api");
HttpClient client = new HttpClient();
client.DefaultRequestHeaders.Authorization
= new AuthenticationHeaderValue("Bearer", apiKey.Value);
var response = await client.PostAsJsonAsync("https://api.whereby.dev/v1/meetings", roomRequest);
string jsonString = await response.Content.ReadAsStringAsync();
RoomRequestResponse? returnValue=
JsonSerializer.Deserialize<RoomRequestResponse>(jsonString);