我在python中创建了一个脚本来获取连接到javascript链接的电话号码,该链接在网页上显示为Phone Us
。我知道我可以使用selenium点击该链接并等到数字可见以便解析,但我不想去那条路线。
但是,当我在打开chrome dev工具后手动点击该链接以查看xhr选项卡中的网络活动时,我可以找到此链接https://www.cv-library.co.uk/account-contact-details?id=192205
以及以下标题,这会生成一些包含我之后的电话号码的json响应。
从chrome dev工具获取的标题:
:authority: www.cv-library.co.uk
:method: GET
:path: /account-contact-details?id=192205
:scheme: https
accept: application/json, text/javascript, */*; q=0.01
accept-encoding: gzip, deflate, br
accept-language: en-US,en;q=0.9,bn;q=0.8
cookie: job_search_bar_variant=variant_C_labels_above; _ga=GA1.3.807796815.1553681717; _gid=GA1.3.728310157.1553681717; _gcl_au=1.1.1379982900.1553681717; _fbp=fb.2.1553681722126.942064476; tempbasket=1553681845451186016; ui_hidecookienotice=1; session=1553697454.46289%3ABQkDAAAAAA%3D%3D%3A375400f1f62664342b2c0bd1e6bcd9c89170768b; _gat_UA-23741307-1=1
referer: https://www.cv-library.co.uk/list-jobs/276692/Allen-York-Built-and-Natural-Environment-Ltd
user-agent: Mozilla/5.0 (Windows NT 6.1) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/73.0.3683.86 Safari/537.36
x-requested-with: XMLHttpRequest
一般部分如下所示:
Request URL: https://www.cv-library.co.uk/account-contact-details?id=192205
Request Method: GET
Status Code: 200
Remote Address: 109.169.5.15:443
Referrer Policy: no-referrer-when-downgrade
它在浏览器中产生的响应:
{email: "", telephone: "01202 888986"}
我试过这个:
import requests
url = "https://www.cv-library.co.uk/account-contact-details?id=192205"
headers = {
'referer': 'https://www.cv-library.co.uk/list-jobs/276692/Allen-York-Built-and-Natural-Environment-Ltd',
'user-agent': 'Mozilla/5.0 (Windows NT 6.1) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/73.0.3683.86 Safari/537.36'
}
with requests.Session() as s:
res = s.get(url,headers=headers).json()
print(res)
它抛出的错误:
raise JSONDecodeError("Expecting value", s, err.value) from None
json.decoder.JSONDecodeError: Expecting value: line 7 column 1 (char 6)
如何使用请求获取该电话号码?
尝试在标题中添加'x-requested-with':'XMLHttpRequest'
:
import requests
url = "https://www.cv-library.co.uk/account-contact-details"
headers = {
'x-requested-with': 'XMLHttpRequest',
'user-agent': 'Mozilla/5.0 (Windows NT 6.1) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/73.0.3683.86 Safari/537.36'}
payload = {'id':'192205'}
with requests.Session() as s:
res = s.get(url,headers=headers, params=payload).json()
print(res)
输出:
print (res['telephone'])
01202 888986