highchart网络网络图

问题描述 投票:0回答:1

我正在使用highchart创建网络图。我需要更改工具提示值。但它不起作用。

请检查我的代码

var json = [{
    "key": "1",
    "value": "19122",
    "code": "A"
  }, {
    "key": "19122",
    "value": "623753",
     "code": "B"
  }, {
    "key": "19122",
    "value": "582024",
     "code": "C"
  }],
  data = [];

json.forEach(function(point) {
 data.push([point.key, point.value])
});

Highcharts.chart('container', {

  tooltip: {
    formatter: function() {
     return data.code;
    }
  },

  series: [{
    type: 'networkgraph',
    layoutAlgorithm: {
      enableSimulation: true
    },
     dataLabels: {
            enabled: true,
            linkFormat: ''
        },
    data
  }]

});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/2.2.1/jquery.min.js"></script>
<script src="https://code.highcharts.com/highcharts.js"></script>
<script src="https://code.highcharts.com/modules/networkgraph.js"></script>
<div id="container"></div>

当我将鼠标悬停在网络葡萄节点上时,我需要显示代码值。我该怎么做。

javascript jquery highcharts
1个回答
2
投票

尝试一下:

var json = [{
    "key": "1",
    "value": "19122",
    "code": "A"
  }, {
    "key": "19122",
    "value": "623753",
     "code": "B"
  }, {
    "key": "19122",
    "value": "582024",
     "code": "C"
  }],
  data = [];

json.forEach(function(point) {
 data.push([point.key, point.value])
});

Highcharts.chart('container', {

  tooltip: {
    formatter: function() {
      const codes = json.reduce((acc, cur)=>{
        if(cur.key===this.key||cur.value===this.key) acc.push(cur.code);
        return acc;}, []);
      return codes.join(',');         
    }
  },

  series: [{
    type: 'networkgraph',
    layoutAlgorithm: {
      enableSimulation: true
    },
     dataLabels: {
            enabled: true,
            linkFormat: ''
        },
    data
  }]

});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/2.2.1/jquery.min.js"></script>
<script src="https://code.highcharts.com/highcharts.js"></script>
<script src="https://code.highcharts.com/modules/networkgraph.js"></script>
<div id="container"></div>
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