有什么方法可以将这个if函数转换为切换大小写类型吗？

Question

if (textLetter.toLowerCase().contains('1')) {
      textCodeElec += ' 19';
      textLetter = textLetter.substring(1); 
    }
    if (textLetter.toLowerCase().contains('2')) {
      textCodeElec += ' 00';
      textLetter = textLetter.substring(1);
    }
    if (textLetter.toLowerCase().contains('3')) {
      textCodeElec += ' 70';
      textLetter = textLetter.substring(1);
    }
    if (textLetter.toLowerCase().contains('4')) {
      textCodeElec += ' 08';
      textLetter = textLetter.substring(1);
    }
    if (textLetter.toLowerCase().contains('5')) {
      textCodeElec += ' 56';
      textLetter = textLetter.substring(1);
    }
    if (textLetter.toLowerCase().contains('6')) {
      textCodeElec += ' 68';
      textLetter = textLetter.substring(1);
    }
    if (textLetter.toLowerCase().contains('7')) {
      textCodeElec += ' 20';
      textLetter = textLetter.substring(1);
    }
    if (textLetter.toLowerCase().contains('8')) {
      textCodeElec += ' 16';
      textLetter = textLetter.substring(1);
    }
    if (textLetter.toLowerCase().contains('9')) {
      textCodeElec += ' 27';
      textLetter = textLetter.substring(1);
    }

我还是不知道如何解决这个问题 当输入1到9时，textCodeElec会有条件地显示，但向后输入9到1只会显示数字。

Answer 1

尝试一下，我希望它能解决您的问题。

String someFunc(val) {
  String textLetter = val;
  final textToList = textLetter.split('');
  // textToList.sort();//if you need to sorted number uncomment this line
  final result = textToList.map((e) => codecVal(e)).toList();
  return result.join("");
}

String codecVal(val) {
  switch (val) {
    case '1':
      return ' 19';
    case '2':
      return ' 00';
    case '3':
      return ' 70';
    case '4':
      return ' 08';
    case '5':
      return ' 56';
    case '6':
      return ' 68';
    case '7':
      return ' 20';
    case '8':
      return ' 16';
    case '9':
      return ' 27';
    default:
      return "";
  }
}

输入=987654321

输出= 27 16 20 68 56 08 70 00 19

---

输入=123456789

输出=19 00 70 08 56 68 20 16 27