在DataGridView中单击链接按钮时，如何调用crystal report viewer？

Question

我使用datagridview创建了一个订单webform，我使用crystal report创建了一个报表。我还将crystalreportviewer放到datagridview同一页面。

这是webform和datagridview的gridview列的列表：

<asp:GridView ID="GridViewHome" runat="server"  AllowPaging="True" AutoGenerateColumns="false" BackColor="White" BorderColor="#CC9966" BorderStyle="None" BorderWidth="1px" CellPadding="4" OnPageIndexChanging="GridViewHome_PageIndexChanging">

           <Columns>
            <asp:TemplateField>
                <HeaderTemplate>Patient MRN#</HeaderTemplate>
                <ItemTemplate>
                    <asp:Label ID="lblpatient" runat="server" Text='<%# Eval("Patient No") %>'></asp:Label>
                </ItemTemplate>
            </asp:TemplateField>
            <asp:TemplateField>
                <HeaderTemplate>Order Number</HeaderTemplate>
                <ItemTemplate>
                    <asp:Label ID="lblorder" runat="server" Text='<%# Eval("Request number") %>'></asp:Label>
                </ItemTemplate>
            </asp:TemplateField>
            <asp:TemplateField>
                <HeaderTemplate>Patient Name</HeaderTemplate>
                <ItemTemplate>
                    <asp:Label ID="lblname" runat="server" Text='<%# Eval("Patient Name") %>'></asp:Label>
                </ItemTemplate>
            </asp:TemplateField>
            <asp:TemplateField>
                <HeaderTemplate>Req. Date</HeaderTemplate>
                <ItemTemplate>
                    <asp:Label ID="lblreqd" runat="server" Text='<%# Eval("Request Date") %>'></asp:Label>
                </ItemTemplate>
            </asp:TemplateField>

            <asp:TemplateField>
                <HeaderTemplate>Report Date</HeaderTemplate>
                <ItemTemplate>
                    <asp:Label ID="lblrepd" runat="server" Text='<%# Eval("Report Date") %>'></asp:Label>
                </ItemTemplate>
            </asp:TemplateField>
             <asp:TemplateField>
                <HeaderTemplate>Test Name</HeaderTemplate>
                <ItemTemplate>
                    <asp:Label ID="LblTest" runat="server" Text='<%# Eval("Test_Name") %>'></asp:Label>
                </ItemTemplate>
            </asp:TemplateField>

            <asp:TemplateField>
                <HeaderTemplate>Result</HeaderTemplate>
                <ItemTemplate>
                    <asp:Label ID="result" runat="server" Text='<%# Eval("Result") %>'></asp:Label>
                </ItemTemplate>
            </asp:TemplateField>

            <asp:TemplateField>
                <HeaderTemplate>Ref.Range From</HeaderTemplate>
                <ItemTemplate>
                    <asp:Label ID="Reflow" runat="server" Text='<%# Eval("Low Range") %>'></asp:Label>
                </ItemTemplate>
            </asp:TemplateField>

            <asp:TemplateField>
                <HeaderTemplate>To</HeaderTemplate>
                <ItemTemplate>
                    <asp:Label ID="refhigh" runat="server" Text='<%# Eval("High Range") %>'></asp:Label>
                </ItemTemplate>
            </asp:TemplateField>

            <asp:TemplateField>
                <HeaderTemplate>Text Range</HeaderTemplate>
                <ItemTemplate>
                    <asp:Label ID="textrange" runat="server" Text='<%# Eval("Text Range") %>'></asp:Label>
                </ItemTemplate>
            </asp:TemplateField>

            <asp:TemplateField>
                <HeaderTemplate>REQ. FORM NO.</HeaderTemplate>
                <ItemTemplate>
                    <asp:Label ID="req" runat="server" Text='<%# Eval("REQ FORM NUMBER") %>'></asp:Label>
                </ItemTemplate>
            </asp:TemplateField>

            <asp:TemplateField>
                <HeaderTemplate>Dept.Id</HeaderTemplate>
                <ItemTemplate>
                    <asp:Label ID="deptid" runat="server" Text='<%# Eval("DEPT ID") %>'></asp:Label>
                </ItemTemplate>
            </asp:TemplateField>

            <asp:TemplateField>
                <HeaderTemplate>Department</HeaderTemplate>
                <ItemTemplate>
                    <asp:Label ID="deptname" runat="server" Text='<%# Eval("Department") %>'></asp:Label>
                </ItemTemplate>
            </asp:TemplateField>

            <asp:TemplateField>
                <HeaderTemplate>Options</HeaderTemplate>
                <ItemTemplate>
                    <asp:LinkButton ID="Lnkresult"  runat="server" OnClick="Lnkresult_Click">Print Result</asp:LinkButton>
                </ItemTemplate>
            </asp:TemplateField>

        </Columns>

这是gridview图片：

我希望按下链接按钮（打印结果）根据OrderNum和deptid参数显示报告down datagridview。

我创建了linkbutton，我使用了以下代码：

protected void Lnkresult_Click(object sender, EventArgs e)
        {
            GridViewRow iRow = ((GridViewRow)((LinkButton)sender).NamingContainer);

            //Assuming you first column is where your "lblOrder" is.
           int OrderNum = Convert.ToInt32(((Label)iRow.Cells[1].Controls[1]).Text);
           int Deptid = Convert.ToInt32(((Label)iRow.Cells[11].Controls[1]).Text);

            ReportDocument myReportDocument;
            myReportDocument = new ReportDocument();
            myReportDocument.Load(Server.MapPath("~/RPT/RPT_RESULTS.rpt"));
            myReportDocument.SetParameterValue("@ORDER_ID", OrderNum);
            myReportDocument.SetParameterValue("@deptid", Deptid);
            myReportDocument.SetDatabaseLogon("username", "password");
            CrystalReportViewer1.ReportSource = myReportDocument;
            CrystalReportViewer1.DisplayToolbar = true;
        }

但当我点击链接按钮时，它不会显示报告我的代码有什么错误？

Answer 1

您可以在datagridview中添加超链接并调用webform并使用以下代码将参数发送到crystal report查看器：

<asp:TemplateField>
                    <HeaderTemplate>Options</HeaderTemplate>
                    <ItemTemplate>
                         <asp:HyperLink ID="HyperLink1"  NavigateUrl='<%#"/RPT/WebForm1.aspx?order_id=" +Eval("Request number")+"&DEPT ID=" +Eval("DEPT ID")+"&Test Id=" +Eval("Test Id")%>' runat="server">Print Result</asp:HyperLink>
                    </ItemTemplate>
                </asp:TemplateField>

并在webform的页面加载中创建文本框2或3或4文本框的数量取决于您的参数然后在页面加载中使用此代码：

protected void Page_Load(object sender, EventArgs e)
        {

            if (!IsPostBack)
            {

              TXTORDERID.Text = Request.QueryString["order_id"].ToString();
                TXTDEPTID.Text = Request.QueryString["DEPT ID"].ToString();
                TXTTESTID.Text = Request.QueryString["Test Id"].ToString();
                ReportDocument reportDocument = new ReportDocument();
                ParameterFields paramFields = new ParameterFields();
                ParameterField paramField = new ParameterField();
                ParameterDiscreteValue paramDiscreteValue = new ParameterDiscreteValue();



                        paramField.Name = "@ORDER_ID";
                        paramDiscreteValue.Value = TXTORDERID.Text.ToString();
                        paramField.CurrentValues.Add(paramDiscreteValue);
                        paramFields.Add(paramField);

                        paramField = new ParameterField(); 
                        paramDiscreteValue = new ParameterDiscreteValue();  
                        paramField.Name = "@deptid";
                        paramDiscreteValue.Value = TXTDEPTID.Text.ToString();
                        paramField.CurrentValues.Add(paramDiscreteValue);
                        paramFields.Add(paramField);

                        CrystalReportViewer1.ParameterFieldInfo = paramFields;
                        CrystalReportViewer1.ReuseParameterValuesOnRefresh = true;
                        CrystalReportViewer1.ToolPanelView = CrystalDecisions.Web.ToolPanelViewType.None;
                        reportDocument.Load(Server.MapPath("~/RPT/RPT_RESULT.rpt"));
                        CrystalReportViewer1.ReportSource = reportDocument;
                        reportDocument.SetDatabaseLogon("DBA", "2006");
                    }
                }