如何读取屏幕像素?

问题描述 投票:13回答:6

我想读一个矩形区域,或整个屏幕像素。好像按下了屏幕截图按钮。

我怎么做的?

编辑:工作代码:

void CaptureScreen(char *filename)
{
    int nScreenWidth = GetSystemMetrics(SM_CXSCREEN);
    int nScreenHeight = GetSystemMetrics(SM_CYSCREEN);
    HWND hDesktopWnd = GetDesktopWindow();
    HDC hDesktopDC = GetDC(hDesktopWnd);
    HDC hCaptureDC = CreateCompatibleDC(hDesktopDC);
    HBITMAP hCaptureBitmap = CreateCompatibleBitmap(hDesktopDC, nScreenWidth, nScreenHeight);
    SelectObject(hCaptureDC, hCaptureBitmap); 

    BitBlt(hCaptureDC, 0, 0, nScreenWidth, nScreenHeight, hDesktopDC, 0,0, SRCCOPY|CAPTUREBLT); 

    BITMAPINFO bmi = {0}; 
    bmi.bmiHeader.biSize = sizeof(bmi.bmiHeader); 
    bmi.bmiHeader.biWidth = nScreenWidth; 
    bmi.bmiHeader.biHeight = nScreenHeight; 
    bmi.bmiHeader.biPlanes = 1; 
    bmi.bmiHeader.biBitCount = 32; 
    bmi.bmiHeader.biCompression = BI_RGB; 

    RGBQUAD *pPixels = new RGBQUAD[nScreenWidth * nScreenHeight]; 

    GetDIBits(
        hCaptureDC, 
        hCaptureBitmap, 
        0,  
        nScreenHeight,  
        pPixels, 
        &bmi,  
        DIB_RGB_COLORS
    );  

    // write:
    int p;
    int x, y;
    FILE *fp = fopen(filename, "wb");
    for(y = 0; y < nScreenHeight; y++){
        for(x = 0; x < nScreenWidth; x++){
            p = (nScreenHeight-y-1)*nScreenWidth+x; // upside down
            unsigned char r = pPixels[p].rgbRed;
            unsigned char g = pPixels[p].rgbGreen;
            unsigned char b = pPixels[p].rgbBlue;
            fwrite(fp, &r, 1);
            fwrite(fp, &g, 1);
            fwrite(fp, &b, 1);
        }
    }
    fclose(fp);

    delete [] pPixels; 

    ReleaseDC(hDesktopWnd, hDesktopDC);
    DeleteDC(hCaptureDC);
    DeleteObject(hCaptureBitmap);
}
c++ windows screen-capture
6个回答
11
投票

从您的代码开始并省略错误检查......

// Create a BITMAPINFO specifying the format you want the pixels in.
// To keep this simple, we'll use 32-bits per pixel (the high byte isn't
// used).
BITMAPINFO bmi = {0};
bmi.bmiHeader.biSize = sizeof(bmi.bmiHeader);
bmi.bmiHeader.biWidth = nScreenWidth;
bmi.bmiHeader.biHeight = nScreenHeight;
bmi.bmiHeader.biPlanes = 1;
bmi.bmiHeader.biBitCount = 32;
bmi.bmiHeader.biCompression = BI_RGB;

// Allocate a buffer to receive the pixel data.
RGBQUAD *pPixels = new RGBQUAD[nScreenWidth * nScreenHeight];

// Call GetDIBits to copy the bits from the device dependent bitmap
// into the buffer allocated above, using the pixel format you
// chose in the BITMAPINFO.
::GetDIBits(hCaptureDC,
            hCaptureBitmap,
            0,  // starting scanline
            nScreenHeight,  // scanlines to copy
            pPixels,  // buffer for your copy of the pixels
            &bmi,  // format you want the data in
            DIB_RGB_COLORS);  // actual pixels, not palette references

// You can now access the raw pixel data in pPixels.  Note that they are
// stored from the bottom scanline to the top, so pPixels[0] is the lower
// left pixel, pPixels[1] is the next pixel to the right,
// pPixels[nScreenWidth] is the first pixel on the second row from the
// bottom, etc.

// Don't forget to free the pixel buffer.
delete [] pPixels;


3
投票

重读你的问题,听起来我们可能已经开始与屏幕截图相切。如果您只想检查屏幕上的某些像素,可以使用GetPixel

HDC hdcScreen = ::GetDC(NULL);
COLORREF pixel = ::GetPixel(hdcScreen, x, y);
ReleaseDC(NULL, hdcScreen);
if (pixel != CLR_INVALID) {
  int red = GetRValue(pixel);
  int green = GetGValue(pixel);
  int blue = GetBValue(pixel);
  ...
} else {
  // Error, x and y were outside the clipping region.
}

如果您要读取大量像素,那么最好使用屏幕截图然后使用GetDIBits。调用GetPixel数十亿次将是缓慢的。


2
投票

你用BitBlt()制作截图。使用nWidth和nHeight参数设置镜头的大小。左上角设置了nXSrc和nYSrc参数。


1
投票

您可以使用下面的代码来读取屏幕像素:

HWND desktop = GetDesktopWindow();
HDC desktopHdc = GetDC(desktop);
COLORREF color = GetPixel(desktopHdc, x, y);

0
投票

HBITMAP不是指针或数组,它是由Windows管理的句柄,仅对Windows有意义。您必须要求Windows将像素复制到某处以供使用。

要获得单个像素值,您可以使用GetPixel,甚至不需要位图。如果您需要访问许多像素,这将很慢。

要将位图复制到内存,您可以访问,使用GetDIBits function

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