Ansible - VMWARE

Question

我正在开发 Ansible 角色来删除 VMWARE 快照。 但是，因为删除所有这些文件可能很容易，所以我想删除那些名称与特定字符串匹配且早于 x 天的文件。

为了实现该目标，我首先使用 vmware_guest_snapshot_info 集合收集每个虚拟机的快照详细信息。这是最简单的部分。 我将输出注册在一个变量中（不知道 Ansible 是如何定义它的）。 我最终得到了以下字典：

{"changed": false, 
"guest_snapshots": 
{
 "current_snapshot": 
  {"creation_time": "2023-06-06T18:31:37.532826+00:00", 
   "description": "Snapshot TEST", 
   "id": 1243,    
   "name": "Patching_Linux2023-06-06", 
   "state": "poweredOff"
  }, 
  "snapshots": [
   {"creation_time": "2023-06-06T14:38:17.909158+00:00", 
   "description": "", 
   "id": 1242, 
   "name": "Linux_test", 
   "state": "poweredOff"
   }, 
   {
    "creation_time": "2023-06-06T18:31:37.532826+00:00", 
    "description": "Snapshot TEST", 
    "id": 1243, "name": "Patching_Linux2023-06-06", 
    "state": "poweredOff"
   }
   ]
  }
}

我需要考虑到我可能有多个快照。 我尝试使用以下 Ansible 任务进行删除（起初我没有专注于快照年龄）：

第一枪是：

- name: Remove old snapshots
  vmware_guest_snapshot:
    hostname: "{{ vcenter_hostname_uni }}"
    username: "{{ vcenter_username }}"
    password: "{{ vcenter_password }}"
    datacenter: myvcenter
    validate_certs: no
    #name: "{{ inventory_hostname |upper }}"
    folder: "{{ vm_folders }}"
    vm_id: "{{ item.item }}"
    snapshot_name: "{{ item.name }}"
    state: absent
  delegate_to: "{{vcenter_launcher_uni }}"
  loop: "{{ snapshots_info.name }}"
  when: item.name is search('Patching_Linux') 
   tags:
    - clean_patching_snap 

我已经尝试了其他带有循环和with_items条件的东西，但我仍然无法弄清楚如何访问所有快照名称。

有什么想法吗？

Answer 1

应该这样做：

列出快照

```
- name: Find all sanpshots
  vmware_guest_snapshot_info:
    hostname: "{{ vcenter_hostname_uni }}"
    username: "{{ vcenter_username }}"
    password: "{{ vcenter_password }}"
    datacenter: myvcenter
    validate_certs: no
    name: "{{ inventory_hostname |upper }}"
    folder: "{{ vm_folders }}"
  delegate_to: "{{vcenter_launcher_uni }}"
  register: snapshots_info
  tags:
    - list_snap
    - clean_patching_snap```

删除名称中包含特定模式的快照：

```
- name: Remove old snapshots
  vmware_guest_snapshot:
    hostname: "{{ vcenter_hostname_uni }}"
    username: "{{ vcenter_username }}"
    password: "{{ vcenter_password }}"
    datacenter: myvcenter
    validate_certs: no
    name: "{{ inventory_hostname |upper }}"
    folder: "{{ vm_folders }}"
    snapshot_name: "{{ item.name }}"
    state: absent
  delegate_to: "{{vcenter_launcher_uni }}"
  loop: "{{ snapshots_info.guest_snapshots.snapshots }}"
  when: item.name is search('MyPatternName')```

我仍然坚持选择那些超过定义天数的内容。

添加这个没有帮助： ` 和 (ansible_date_time.epoch - (item.creation_time | int)) > 4 * 86400)

Something like this will probably work but I am stucked with the exact syntax

'{{ (( ansible_date_time.iso8601 | to_datetime('%Y-%m-%dT%H:%M:%S.%f%z')) - (item.creation_time | to_datetime('%Y-%m-%dT%H:%M:%S.%f%z')) > (4 * 24 * 60 * 60) and item.name is search('Patching_Linux') }}'
It gives an error

Answer 2

您还在寻找解决方案吗？