我正在阅读 Bruce Eckel 的书 “Thinking in C++”,vol. 2 在做第 11 章的练习 13 时,我遇到了一个问题。
练习 13:创建两个 Runnable 子类,其中一个子类具有启动并调用 wait() 的 run()。另一个类的 run() 应该捕获第一个 Runnable 对象的引用。它的 run() 应该在经过几秒后调用第一个线程的 signal() ,以便第一个线程可以打印消息。
Runnable 类来自 ZThreads 库。
这是我的代码:
#include <iostream>
#include "zthread/Runnable.h"
#include "zthread/Condition.h"
#include "zthread/Mutex.h"
#include "zthread/Guard.h"
#include "zthread/CountedPtr.h"
#include "zthread/Thread.h"
class Class1: public ZThread::Runnable {
ZThread::Mutex lock;
ZThread::Condition condition;
public:
Class1(): condition(lock) {}
void run() {
ZThread::Guard<ZThread::Mutex> g(lock);
std::cout << "Class1::run()\n";
condition.wait();
std::cout << "Message\n";
}
void continue1() {
ZThread::Guard<ZThread::Mutex> g(lock);
std::cout << "Class1::continue1()\n";
condition.signal();
}
};
class Class2: public ZThread::Runnable {
ZThread::CountedPtr<Class1>& c;
public:
Class2(ZThread::CountedPtr<Class1>& c1): c(c1) {}
void run() {
std::cout << "Class2::run()\n";
ZThread::Thread::sleep(2000);
std::cout << "Calling continue1()\n";
c->continue1();
std::cout << "Exiting Class2::run()\n";
}
};
int main() {
ZThread::CountedPtr<Class1> c(new Class1);
std::cout << "Starting thread 1\n";
ZThread::Thread t1(c);
std::cout << "Starting thread 2\n";
ZThread::Thread t2(new Class2(c));
std::cout << "exit\n";
}
它挂起并且不打印“消息”。我做错了什么?
您的程序以 main 函数结束,两个线程都被中断。将休眠添加到主函数的末尾。