tkinter - 使用 grid_slaves 从函数调用网格值

Question

我正在尝试使用 grid_slaves 从函数创建列网格数据列表。我希望该函数获取列中的每个网格值，然后附加到列表中。没有创建列表，但打印前 3 个列表会产生：

[[<tkinter.Entry object .!labelframe.!entry>]] [[<tkinter.Entry object .!labelframe.!entry2>]] [[<tkinter.Entry object .!labelframe.!entry3>]]
[[<tkinter.Entry object .!labelframe.!entry>], [<tkinter.Entry object .!labelframe.!entry7>]] [[<tkinter.Entry object .!labelframe.!entry2>], [<tkinter.Entry object .!labelframe.!entry8>]] [[<tkinter.Entry object .!labelframe.!entry3>], [<tkinter.Entry object .!labelframe.!entry9>]]

from tkinter import*
 root = Tk()

 def make_list(num_rows): # Make array of value columns
    #Create empty lists
    value1_list=[]
    value2_list=[]
    value3_list=[]
    value4_list=[]
    value5_list=[]
    value6_list=[]

    #Obtain values in frame 1 grid
    for j in range(2,num_rows+2):
       # Obtain values in each column
       value1_column = frame1.grid_slaves(row=j, column=1)
       value2_column = frame1.grid_slaves(row=j, column=2)
       value3_column = frame1.grid_slaves(row=j, column=3)
       value4_column = frame1.grid_slaves(row=j, column=4)
       value5_column = frame1.grid_slaves(row=j, column=5)
       value6_column = frame1.grid_slaves(row=j, column=6)
       # Fill lists with frame 1 column values
       value1_list.append(value1_column)
       value2_list.append(value2_column)
       value3_list.append(value3_column)
       value4_list.append(value4_column)
       value5_list.append(value5_column)
       value6_list.append(value6_column)

       print(value1_list, value2_list, value3_list) # output above

 #Create Make List GUI
 width= root.winfo_screenwidth()               
 height= root.winfo_screenheight()  
 root.title("Value Frame")        
 root.geometry("%dx%d" % (width, height))# Set GUI to full screen
 frame1 = Frame(root) #Create frame for input boxes   
 frame1=LabelFrame(root, text='Value Frame 1',padx=10, pady=10)
 frame1.grid(row=0, column=0)

 #Frame 1 labels
 label1 = Label(frame1, text='value 1',pady=2) 
 label1.grid(row=1, column=1)
 label2 = Label(frame1, text='value 2',pady=2) 
 label2.grid(row=1, column=2)
 label3 = Label(frame1, text='value 3',pady=2) 
 label3.grid(row=1, column=3)
 label4 = Label(frame1, text='value 4',pady=2) 
 label4.grid(row=1, column=4)
 label5 = Label(frame1, text='value 5',pady=2) 
 label5.grid(row=1, column=5)
 label6 = Label(frame1, text='value 6',pady=2) 
 label6.grid(row=1, column=6)

 num_rows = 2
 for i in range(num_rows):
   # Label row No
   label1 = Label(frame1, text=f'# {i+1}',pady=2) 
   label1.grid(row= 2+i, column=0)
  
   #Enter Data Frame 1
   value1 = Entry(frame1,width=10)
   value2 = Entry(frame1,width=10)
   value3 = Entry(frame1,width=10)
   value4 = Entry(frame1,width=10)
   value5 = Entry(frame1,width=10)
   value6 = Entry(frame1,width=10)

   #Grid Location Frame 1
   value1.grid(row=i+2, column = 1)
   value2.grid(row=i+2, column = 2)
   value3.grid(row=i+2, column = 3)
   value4.grid(row=i+2, column = 4)
   value5.grid(row=i+2, column = 5)
   value6.grid(row=i+2, column = 6)

   # Prefill grid values
   value1.insert(0, int("5")) 
   value2.insert(0, int("2")) 
   value3.insert(0, int("4")) 
   value4.insert(0, int("8")) 
   value5.insert(0, int("6")) 
   value6.insert(0, int("1")) 

 #Create submit button and call Make List function
 myButton = Button(root, text='Make List', command = lambda:make_list(num_rows))
 myButton.grid(row = 0, column = 15, sticky = N, padx = 40, pady=10)

 root.mainloop()

如有任何建议，将不胜感激。

尝试了多种不同的 grid_slave 配置，但无法创建列表

Answer 1

您缺少的部分是您必须在每个条目上调用

.get()

才能获取值。

此外，您还可以更好地利用循环。无论您有多少行或列，以下函数都可以工作，并且不需要那么多行代码。

我让它打印值并返回值。返回值是没有意义的，因为您是从按钮命令调用它的，但如果您想引用

lambda

内的值，或在

lambda

之外调用此函数，它就在那里。

def make_list(num_rows):
    results = []
    for r in range(2, num_rows+2):
        # add a new row to our results
        row = []
        results.append(row)

        for c in range(1,7):
            # slaves will be a list with one value.
            slaves = frame1.grid_slaves(row=r, column=c)
            entry = slaves[0]

            # get the value, append it to the list of values
            # for this row
            value = entry.get()
            row.append(value)

    print(results)
    return results