我有这样的地图,有彩色国家和黑色边框。
我需要一种方法来提取地图上每个国家(红色)的所有邻国(蓝色)。
结果应该是这样的:
{
"country1":{
"neighbours":["country2","country3","country4","country5","country6","country7","country8"]
},
"country2":{
"neighbours":["country1","country8","country9","country10"]
},
...
}
到目前为止,我已按照建议使用 potrace 和 PIL 将其转换为矢量 (.svg),以使地图更易于使用 此结果(SVG 文件的图像。我无法上传 SVG。)
import os
from PIL import Image
threshold = 620
file_in = "/Users/nils/Documents/map.png"
img = Image.open(file_in)
pixels = list(img.getdata())
newPixels = []
for pixel in pixels:
if pixel[0]+pixel[1]+pixel[2] <= threshold:
newPixel = (0, 0, 0)
else:
newPixel = (255, 255, 255)
newPixels.append(newPixel)
newImg = Image.new(img.mode, img.size)
newImg.putdata(newPixels)
file_out = "test.bmp"
print (len(newImg.split())) # test
if len(newImg.split()) == 4:
print("converting")
r, g, b, a = newImg.split()
newImg = Image.merge("RGB", (r, g, b))
newImg.save(file_out)
else:
newImg.save(file_out)
os.system("potrace test.bmp --svg -o my.svg")
首先是源图像,其次是结果图的插图(单击它们):
方法:
import numpy as np
import cv2 as cv
import matplotlib.pyplot as plt
im = cv.imread("7oPxiEBe.png")
(height, width) = im.shape[:2]
gray = cv.cvtColor(im, cv.COLOR_BGR2GRAY)
(th, mask) = cv.threshold(gray, 192, 255, cv.THRESH_BINARY)
这张图片看起来像白色背景上的黑色线条,但您应该将其视为黑色背景上的白色斑点:
# remove small components
# near egypt, the borders enclose 1-2 pixel sized components of sea
(num_labels, labels, stats, centroids) = cv.connectedComponentsWithStats(mask, connectivity=4)
for i in range(num_labels):
if stats[i, cv.CC_STAT_AREA] <= 2:
mask[labels == i] = 0
# the actual labeling
(num_labels, labels, stats, centroids) = cv.connectedComponentsWithStats(mask, 8, cv.CV_32S)
# calculate a central point for each component
# that's just for visualization
# give the "sea" label a border so its central point doesn't stick to a corner of the picture
modified_mask = mask.copy()
modified_mask[:,0] = 0
modified_mask[:,-1] = 0
modified_mask[0,:] = 0
modified_mask[-1,:] = 0
dist = cv.distanceTransform(modified_mask, cv.DIST_L2, cv.DIST_MASK_PRECISE)
central_points = []
for label in range(num_labels):
component_dist = np.where(labels == label, dist, 0)
(minVal, maxVal, minLoc, maxLoc) = cv.minMaxLoc(component_dist)
central_points.append(maxLoc)
central_points = np.array(central_points)
# now let's establish neighbor relationships
# for each component mask,
# dilate the component mask by a few pixels,
# calculate intersection with (original mask - component mask)
# collect the labels in the intersection
# own label might show up, shouldn't (assertion). any collected labels are neighbors.
adjacency = np.zeros((num_labels, num_labels), dtype=bool)
# label 0 (borders): neighbor to everyone, that's useless
# label 1 (sea/background): neighbor to coastal countries
for label in range(num_labels):
if label == 0: continue # borders themselves
# if label == 1: continue # non-continent (sea, other continents)
component = (labels == label)
noncomponent = mask.astype(bool) & ~component
dilated_component = cv.dilate(component.astype(np.uint8), kernel=None, iterations=3).astype(bool)
# NOTE: iterations=1 gives nothing, 2 gives *something* but with obvious missing edges.
intersection = noncomponent & dilated_component
neighbor_labels = np.unique(labels[intersection])
adjacency[label, neighbor_labels] = True
print(f"neighbors of {label:2d}: {set(neighbor_labels)}")
neighbors of 1: {2, 3, 4, 5, 6, 8, 13, 14, 15, 18, 19, 20, 21, 22, 23, 24, 26, 27, 28, 29, 31, 32, 33, 34, 35, 37, 38, 39, 40, 43, 44, 47, 48, 50, 52}
neighbors of 2: {1, 3, 5}
neighbors of 3: {1, 2, 4, 5, 8, 10, 11}
neighbors of 4: {1, 3, 7, 8, 9}
neighbors of 5: {1, 2, 3, 6, 11, 12, 13}
neighbors of 6: {1, 13, 5}
neighbors of 7: {8, 4}
neighbors of 8: {1, 3, 4, 7, 9, 10, 15}
neighbors of 9: {8, 4}
neighbors of 10: {3, 8, 11, 15, 16, 22, 31}
neighbors of 11: {3, 5, 10, 12, 16, 19, 20, 24}
neighbors of 12: {5, 11, 13, 20, 30}
neighbors of 13: {1, 5, 6, 12, 14, 17, 25, 30}
neighbors of 14: {1, 13, 17, 23}
neighbors of 15: {1, 8, 10, 18, 21, 22}
neighbors of 16: {10, 11, 24, 28, 29, 31}
neighbors of 17: {34, 13, 14, 23, 25, 26, 27}
neighbors of 18: {1, 15}
neighbors of 19: {24, 1, 11, 20}
neighbors of 20: {1, 37, 38, 39, 11, 12, 19, 30}
neighbors of 21: {1, 22, 15}
neighbors of 22: {32, 1, 33, 10, 15, 21, 31}
neighbors of 23: {1, 27, 14, 17}
neighbors of 24: {1, 11, 16, 19, 29}
neighbors of 25: {34, 35, 36, 13, 17, 30}
neighbors of 26: {1, 34, 27, 17}
neighbors of 27: {1, 26, 17, 23}
neighbors of 28: {16, 1, 29, 31}
neighbors of 29: {16, 1, 28, 24}
neighbors of 30: {35, 37, 12, 13, 20, 25}
neighbors of 31: {1, 33, 10, 16, 22, 28}
neighbors of 32: {1, 22, 33}
neighbors of 33: {32, 1, 22, 31}
neighbors of 34: {1, 36, 40, 17, 25, 26}
neighbors of 35: {1, 36, 37, 40, 41, 42, 43, 44, 45, 25, 30}
neighbors of 36: {34, 35, 40, 41, 25}
neighbors of 37: {1, 35, 39, 43, 20, 30}
neighbors of 38: {1, 20, 39}
neighbors of 39: {1, 20, 37, 38}
neighbors of 40: {1, 34, 35, 36, 41, 42, 45, 46, 47}
neighbors of 41: {40, 42, 35, 36}
neighbors of 42: {40, 41, 35}
neighbors of 43: {1, 35, 37}
neighbors of 44: {1, 50, 35, 45}
neighbors of 45: {35, 40, 44, 46, 47, 49, 50, 51}
neighbors of 46: {40, 45, 47}
neighbors of 47: {1, 40, 45, 46, 49, 52, 53}
neighbors of 48: {1}
neighbors of 49: {51, 52, 45, 47}
neighbors of 50: {1, 44, 45, 51, 52}
neighbors of 51: {49, 50, 52, 45}
neighbors of 52: {1, 47, 49, 50, 51, 53, 54}
neighbors of 53: {52, 47}
neighbors of 54: {52}
# illustration
scale = 4
canvas = cv.resize((im >> 1), dsize=None, fx=scale, fy=scale, interpolation=cv.INTER_NEAREST)
for i in range(2, num_labels):
for j in range(i+1, num_labels):
if adjacency[i, j]:
#cv.line(canvas, tuple(central_points[i]), tuple(central_points[j]), (0, 255, 0), 1)
cv.line(
img=canvas,
pt1=((central_points[i]+0.5) * scale).astype(int),
pt2=((central_points[j]+0.5) * scale).astype(int),
#color=(186, 186, 186),
color=(255, 255, 255),
thickness=1,
lineType=cv.LINE_AA
)
for i in range(2, num_labels):
cv.putText(
img=canvas,
text=f"{i}",
org=((central_points[i]+0.5) * scale).astype(int),
fontFace=cv.FONT_HERSHEY_SIMPLEX, fontScale=0.5 * scale, color=(255, 255, 255), thickness=round(1 * scale)
)