我如何覆盖easyAdminBundle控制器

问题描述 投票:1回答:1

我想知道如何覆盖EasyAdminBundle控制器。实际上,我想从数据库中编写一些自定义查询,我不想使用dqlFilter。

以下是我的config.yml文件。

 easy_admin:
    site_name: 'site mame .'
    entities:
        User:
            class: EmployeeBundle\Entity\EmployeeLogin
            controller: EmployeeBundle\Controller\UserController
            form:
                fields: ['id', {property : 'userName', label : 'Users'}, {property: 'status', type:'choice', type_options: {choices: {'Active':'1', 'Deactive':'0'}}}]
            new:
                title: 'Add Login'
                form_options: { validation_groups: ['Default', 'EmployeeLogin'] }
                fields: ['-id']
            edit:
                title:  'Edit Login Details'
                form_options: { validation_groups: ['Default'] }
            label: 'Employees'
            list:
                title: "%%entity_label%% customers"
                help: 'The list view overrides the global help message'
                fields: ['id', {property : 'userName', label : 'Users'}, {property: 'status', type: 'boolean'}, {property : 'lastLogin',format: 'D j-n-Y, h:i:s'}]

这是我的UserController,我扩展了BaseAdminController,请告诉我如何从存储库或Controller中自定义查询

namespace EmployeeBundle\Controller;

use JavierEguiluz\Bundle\EasyAdminBundle\Controller\AdminController as BaseAdminController;
use Symfony\Component\HttpFoundation\Request;

class UserController extends BaseAdminController
{
    public function listUserAction()
    {

    }
}
symfony symfony2-easyadmin
1个回答
1
投票

我这样做了,希望它会对别人有所帮助:

public function createListQueryBuilder($entityClass, $sortDirection, $sortField = null, $dqlFilter = null)
      {
          $response =  parent::createListQueryBuilder('EmployeeLogin, EmployeeMaster', $sortDirection, $sortField, $dqlFilter); // TODO: Change the autogenerated stub


          $response->join('entity.userId','emp');
          $response->andWhere('emp.lastName = :role')->setParameter('role', 'sagir');

           return $response;
© www.soinside.com 2019 - 2024. All rights reserved.