如何使用加密狗拨打电话

问题描述 投票:0回答:2

我已经尝试使用加密狗从 Asterisk 拨出电话几个小时。但它显示以下错误

WARNING[22180]: channel.c:166 channel_request: [dongle0] Request to call on device which can not make call at this moment
[Apr ] WARNING[22180]: app_dial.c:2277 dial_exec_full: Unable to create channel of type 'dongle' (cause 44 - Requested channel not available)

拨号方案命令是:

exten => _X.,n,Dial(dongle/dongle0/+73432823232)

您能给我解决方案吗?

更新:在

asterisk*CLI>
我可以使用这个
dongle cmd dongle0 ATD+434343434232;

拨打外线电话
asterisk dongle
2个回答
0
投票

错误表示您配置不正确或设备关闭/拔掉电源

有关更多信息,请启用调试或执行

dongle show devices

https://github.com/bg111/asterisk-chan-dongle


0
投票

根据您的 dialplan 命令出站规则是第一个规则还是后续规则,您可能需要将

n
替换为
1

扩展 => _X.,n,拨号(加密狗/加密狗0/+73432823232)

所以它是这样写的:

exten => _X.,1,Dial(dongle/dongle0/+73432823232)

另外,您是否检查过您的设备是否处于“免费”状态?它应该看起来类似于这样:

asterisk*CLI> dongle show devices
ID           Group State      RSSI Mode Submode Provider Name  Model      Firmware          IMEI             IMSI             Number
dongle0      0     Free       20   0    0       A1             E1550      11.608.13.02.00   123456789012345  123456789012345  +4368112345678

对于编号为 +4368112345678 的加密狗,我有以下入站规则:

(chan_dongle似乎需要在入站规则中定义电话号码)

; inbound rule to call an internal sip-client with extension 6000
exten => +4368012345678,n,Dial(SIP/6000,20,r)
; inbound rule to call some external phone number
exten => +4368012345678,n,Dial(Dongle/dongle0/+436601234567)

对于出站,其工作原理类似:

; outbound rule for call over dongle if match for extension/phonenumber length of 11 (e.g. 06601234567)
exten => _XXXXXXXXXXX,1,Dial(Dongle/dongle0/${EXTEN},40)
; outbound rule for call over dongle if match for extension/phonenumber length of 12 (e.g. 069912345678)
exten => _XXXXXXXXXXXX,1,Dial(Dongle/dongle0/${EXTEN},40)
; outbound rule for call over dongle if match for any extension/phonenumber length
exten => _X.,1,Dial(Dongle/dongle0/${EXTEN},40)
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