如何在javascript中按值将数组拆分为设置大小的块？

Question

我一直在努力解决这个问题，但是我一点也没有运气。我尝试了各种方法，其中一种是forEach数组方法，但无法获得所需的输出。

我有以下数组：

[
  { "CAT": "COLD DRINKS", "QTY": 1, "PRICE": 1.2 },
  { "CAT": "COLD DRINKS", "QTY": 1, "PRICE": 1.5 },
  { "CAT": "QUICK BITES", "QTY": 1, "PRICE": 2.5 },
  { "CAT": "QUICK BITES", "QTY": 1, "PRICE": 3.5 },
  { "CAT": "SANDWICHES", "QTY": 1, "PRICE": 5.3 },
  { "CAT": "SANDWICHES", "QTY": 1, "PRICE": 7.5 }
]

我需要将其分成相等的部分，如下所示：

[
  { "CAT": "COLD DRINKS", "QTY": 1, "PRICE": 1.2 },
  { "CAT": "QUICK BITES", "QTY": 1, "PRICE": 2.5 },
  { "CAT": "SANDWICHES", "QTY": 1, "PRICE": 5.3 }
]

[
  { "CAT": "COLD DRINKS", "QTY": 1, "PRICE": 1.5 },
  { "CAT": "QUICK BITES", "QTY": 1, "PRICE": 3.5 },
  { "CAT": "SANDWICHES", "QTY": 1, "PRICE": 7.5 }
]

抱歉，如果解释不太好。

想法是，每个块都必须具有以下值的所有3个元素。1x冷饮1x三明治1个QUICK BITES

餐费：$ 2.99-1x三明治，1x饮料和1x速食小吃的组合。

第二个数组仅在所有3个值都存在时才应创建。如果仅存在两个值，则循环应中断。

我尝试过的：

var ITM ="";
var PER_CATEGORY_SET = [];
var value = [
      { "CAT": "COLD DRINKS", "QTY": 1, "PRICE": 1.2 },
      { "CAT": "COLD DRINKS", "QTY": 1, "PRICE": 1.5 },
      { "CAT": "QUICK BITES", "QTY": 1, "PRICE": 2.5 },
      { "CAT": "QUICK BITES", "QTY": 1, "PRICE": 3.5 },
      { "CAT": "SANDWICHES", "QTY": 1, "PRICE": 5.3 },
      { "CAT": "SANDWICHES", "QTY": 1, "PRICE": 7.5 }
    ]

value.forEach(function (my_item){
var xx = value.length;

while (xx > 0) {
   if(ITM !=  my_item.CAT ){
   ITM = my_item.CAT;PER_CATEGORY_SET.push({'CAT':my_item.CAT,'QTY':my_item.QTY,'PRICE':my_item.PRICE});
   value.splice(0, 1);
 }
   xx--;
  }
});

我得到的输出如下，它只能创建初始数组，而不执行任何操作：

 [
      { "CAT": "COLD DRINKS", "QTY": 1, "PRICE": 1.2 },
      { "CAT": "QUICK BITES", "QTY": 1, "PRICE": 2.5 },
      { "CAT": "SANDWICHES", "QTY": 1, "PRICE": 5.3 }
 ]

Answer 1

希望对您有帮助

let arr = [
 {"CAT": "COLD DRINKS", "QTY": 1, "PRICE": 1.2}, 
 {"CAT": "COLD DRINKS", "QTY": 1, "PRICE": 1.5},
 {"CAT": "QUICK BITES", "QTY": 1, "PRICE": 2.5},
 {"CAT": "QUICK BITES", "QTY": 1, "PRICE": 3.5},
 {"CAT": "SANDWICHES", "QTY": 1, "PRICE": 5.3},
 {"CAT": "SANDWICHES", "QTY": 1, "PRICE": 7.5}
]

let arr1 = [], arr2 = []

for (let i = 0; i < arr.length; i++ ){
  if(i%2==0) {
  arr1.push(arr[i])
  } else {
  arr2.push(arr[i])
  }
}

console.log(arr1,arr2)

Answer 2

创建2个新数组并循环遍历原始数组一次。如果我是偶数，则推入第一个数组，否则推入第二个数组。

const originalArray =  [
    {"CAT": "COLD DRINKS", "QTY": 1, "PRICE": 1.2}, 
    {"CAT": "COLD DRINKS", "QTY": 1, "PRICE": 1.5},
    {"CAT": "QUICK BITES", "QTY": 1, "PRICE": 2.5},
    {"CAT": "QUICK BITES", "QTY": 1, "PRICE": 3.5},
    {"CAT": "SANDWICHES", "QTY": 1, "PRICE": 5.3},
    {"CAT": "SANDWICHES", "QTY": 1, "PRICE": 7.5}
    ]

 var firstChunk = [];
 var secondChunk = [];

 for(var i = 0; i<originalArray.length; i++){
     if(i%2 === 0){
         firstChunk.push(originalArray[i]);
     }
     else{
         secondChunk.push(originalArray[i]);
     }
 }

您可以分别通过firstChunk和secondChunk访问这两个卡盘