php mongodb $查询DB中的多个键无法正常工作

Question

我有一个问题，当我使用来自mongoDB的值时查询无法工作但在我尝试静态/硬编码值时有效。你能指出我做得不对吗？

当我硬编码如下所示的值时，代码工作正常。

$customer = $this->mongo->selectCollection('bookings');
$cursor = $customer->find(array('provider_id' => "0", 'cat_id' => array('$in' => array('591d380c227951b706e18a56','591da979227951a10f004ad7','591d42292279517209004ad7'))));

但是当值来自mongoDB时，此查询无法正常工作。

$cattype = array();
foreach ($catlist  as $key => $value){ $cattype[] = "'".$value['cid']."'";}
$catlist = implode(',', $cattype);
$customer = $this->mongo->selectCollection('bookings');
$cursor = $customer->find(array('provider_id' => "0", 'cat_id' => array('$in' => array($catlist))));

$catlist = comes from mongoDB

提前致谢

Answer 1

有两个错误：

第一个是你的每一个。您可以添加'...'，而不是添加ID。

foreach ($catlist  as $key => $value){
    $cattype[] = $value['cid']
}

第二个是在你的陈述中。你想传递$cattype数组，但$cattype已经是一个数组，所以你再次将它包装在一个数组中。

$cursor = $customer->find([
    'provider_id' => "0",
    'cat_id' => ['$in' => $catlist]
]);

Answer 2

请使用首先需要转换为mongo id，它可以帮助你。

$cattype = array();
foreach ($catlist  as $key => $value) { 
  $cattype[] = new \MongoId($value['cid']);
}
$catlist = implode(',', $cattype);
$customer = $this->mongo->selectCollection('bookings');
$cursor = $customer->find(array('provider_id' => "0", 'cat_id' => 
array('$in' => array($catlist))));

Answer 3

$cattype = array();
foreach ($catlist  as $key => $value) { 
   $cattype[] = $value['cid'];
}
$catlist = implode(',', $cattype);
$customer = $this->mongo->selectCollection('bookings');
$cursor = $customer->find(array('provider_id' => "0", 'cat_id' => 
      array('$in' => $catlist))
);

Answer 4

我找到了答案。无需破坏$ cattype。只需将$ cattype直接放在$ in array中（'$ in'=> array（$ cattype））