表:
col1 col2 col3 col4 col5 col6 col7 col8 col9
-----------------------------------------------------------------------------
2018-02-22 A B C D 625.2 E K 448
2018-02-22 A B C D 625.2 F L 5.35
2018-02-22 A B C D 625.2 G M 35.71
2018-02-22 A B C D 625.2 H N 87.39
2018-02-22 A B C D 625.2 I O 25.11
2018-02-22 A B C D 625.2 J P 33.93
2018-02-22 A1 B1 C1 D1 14849.5 E1 K1 13294.21
2018-02-22 A1 B1 C1 D1 14849.5 F1 L1 427.03
2018-02-22 A1 B1 C1 D1 14849.5 G1 M1 631.85
2018-02-22 A1 B1 C1 D1 14849.5 H1 N1 326.07
2018-02-22 A1 B1 C1 D1 14849.5 I1 O1 146.36
2018-02-22 A1 B1 C1 D1 14849.5 J1 P1 6.86
结果:
col1 col2 col3 col4 col5 col6 col7 col8 col9
-----------------------------------------------------------------------------
2018-02-22 A B C D 625.2 E K 448
2018-02-22 625.2 F L 5.35
2018-02-22 625.2 G M 35.71
2018-02-22 625.2 H N 87.39
2018-02-22 625.2 I O 25.11
2018-02-22 625.2 J P 33.93
2018-02-22 A1 B1 C1 D1 14849.5 E1 K1 13294.21
2018-02-22 14849.5 F1 L1 427.03
2018-02-22 14849.5 G1 M1 631.85
2018-02-22 14849.5 H1 N1 326.07
2018-02-22 14849.5 I1 O1 146.36
2018-02-22 14849.5 J1 P1 6.86
如果您的表中有任何我们可以对数据进行排序的唯一列,那么我们可以使用LAG
函数,如下所示 -
declare @x table (id int, col1 varchar(10))
insert into @x (id, col1)
select 1, 'A' union all
select 2, 'A' union all
select 3, 'A' union all
select 4, 'A' union all
select 5, 'B' union all
select 6, 'B'
select
id,
col1,
(case when col1 = lag(col1) over (order by id asc) then '' else col1 end) as NewCol
from @x
输出 -
id col1 NewCol
1 A A
2 A
3 A
4 A
5 B B
6 B