使 Seaborn 调色板变暗

Question

我已经有一个我使用的自定义 Seaborn 调色板，例如

pkmn_type_colors_palette = {
    'Grass': '#78C850',
    'Fire': '#F08030',
    'Water': '#6890F0',
    'Bug': '#A8B820',
    'Normal': '#A8A878',
    'Poison': '#A040A0',
    'Electric': '#F8D030',
    'Ground': '#E0C068',
    'Fairy': '#EE99AC',
    'Fighting': '#C03028',
    'Psychic': '#F85888',
    'Rock': '#B8A038',
    'Ghost': '#705898',
    'Ice': '#98D8D8',
    'Dragon': '#7038F8',
    'Dark': sns.xkcd_rgb['dark indigo'],
    'Flying': sns.xkcd_rgb['sky'],
    'Steel': sns.xkcd_rgb['steel'],
}


sns.violinplot(x='Type1', hue='Type1', y='Defense', data=poke_df, palette=pkmn_type_colors_palette)

给出了这样的情节

有没有办法让整个调色板变暗或变亮？但保留映射

Answer 1

您可以将颜色转换为 hsv 颜色模型，并将

value

（亮度）更改为更接近 0：

import matplotlib.pyplot as plt
from matplotlib.colors import rgb_to_hsv, hsv_to_rgb, to_rgb
import seaborn as sns
import pandas as pd
import numpy as np

def darken(color):
    hue, saturation, value = rgb_to_hsv(to_rgb(color))
    return hsv_to_rgb((hue, saturation, value * 0.6))

pkmn_type_colors_palette = {
    'Grass': '#78C850',
    'Fire': '#F08030',
    'Water': '#6890F0',
    'Bug': '#A8B820',
    'Normal': '#A8A878',
    'Poison': '#A040A0',
    'Electric': '#F8D030',
    'Ground': '#E0C068',
    'Fairy': '#EE99AC',
    'Fighting': '#C03028',
    'Psychic': '#F85888',
    'Rock': '#B8A038',
    'Ghost': '#705898',
    'Ice': '#98D8D8',
    'Dragon': '#7038F8',
    'Dark': sns.xkcd_rgb['dark indigo'],
    'Flying': sns.xkcd_rgb['sky'],
    'Steel': sns.xkcd_rgb['steel']
}

poke_df = pd.DataFrame({'Type1': np.repeat(list(pkmn_type_colors_palette), 20)})
poke_df['Defense'] = np.random.randn(len(poke_df)).cumsum()
plt.figure(figsize=(11, 4))
dark_palette = {key: darken(pkmn_type_colors_palette[key]) for key in pkmn_type_colors_palette}
sns.violinplot(x='Type1', hue='Type1', y='Defense', data=poke_df, palette=dark_palette)
plt.tight_layout()
plt.show()