Plotly。如何从一个嵌套的dict中获取一个分组柱状图的y轴值？

Question

这是我最后的字典

{'1': {'Pen': [0.99], 'Note': [1.62]},
 '2': {'Pen': [1.94], 'Note': [2.17]}}

我试图在python中使用plotly绘制组条形图，我得到了我的x值。 [x for x in cdict.keys() for k,v in cdict.items()]

我无法正确地获得Y值。

Answer 1

试试。

y_pen = [cdict[j]["Pen"][0] for j in cdict]
y_note = [cdict[j]["Note"][0] for j in cdict]

---

y_pen:

[0.99, 1.94]

---

y_note:

[1.62, 2.17]

---

Answer 2

在我看来，这就是你要找的东西。

如果是这样的话，你必须为x值做一个列表，比如说 ['Pen', 'Note'] 并检索y值的列表，如 [[0.99, 1.94], [1.62, 2.17]].

完整的代码。

# imports
import plotly.express as px
import plotly.graph_objs as go
import pandas as pd
import numpy as np

cdict = {'1': {'Pen': [0.99], 'Note': [1.62]},
         '2': {'Pen': [1.94], 'Note': [2.17]}}

# get x-values, in this case ['Pen', 'Note']
xVals = list([cdict[k].keys() for k in cdict.keys()][0])

# get y-values, in this case [[0.99, 1.94], [1.62, 2.17]]
yVals = []
for x in xVals:
    yVals.append([cdict[j][x][0] for j in cdict])

# set up plotly figure
fig=go.Figure()

# add trace for each element in yVals
for i, y in enumerate(yVals):
  fig.add_traces(go.Bar(x=xVals, y=y, name = 'Group'+str(i+1)))

fig.show()