假设我们有一个非常简单的服务,它通过id找到一个用户实体:
export class UserService {
constructor(@InjectRepository(UserEntity) private userRepository: Repository<UserEntity>) {
}
async findUser(userId: string): Promise<UserEntity> {
return this.userRepository.findOne(userId);
}
}
然后你可以使用以下模拟工厂模拟UserRepository
(根据需要添加更多方法):
// @ts-ignore
export const repositoryMockFactory: () => MockType<Repository<any>> = jest.fn(() => ({
findOne: jest.fn(entity => entity),
// ...
}));
使用工厂可确保每次测试都使用新的模拟。
describe('UserService', () => {
let service: UserService;
let repositoryMock: MockType<Repository<UserEntity>>;
beforeEach(async () => {
const module: TestingModule = await Test.createTestingModule({
providers: [
UserService,
// Provide your mock instead of the actual repository
{ provide: getRepositoryToken(UserEntity), useFactory: repositoryMockFactory },
],
}).compile();
service = module.get<UserService>(UserService);
repositoryMock = module.get(getRepositoryToken(UserEntity));
});
it('should find a user', async () => {
const user = {name: 'Alni', id: '123'};
// Now you can control the return value of your mock's methods
repositoryMock.findOne.mockReturnValue(user);
expect(service.findUser(user.id)).toEqual(user);
// And make assertions on how often and with what params your mock's methods are called
expect(repositoryMock.findOne).toHaveBeenCalledWith(user.id);
});
});
对于类型安全和舒适,您可以使用以下键入您的模拟(远非完美,当jest本身在即将发布的主要版本中开始使用typescript时可能有更好的解决方案):
export type MockType<T> = {
[P in keyof T]: jest.Mock<{}>;
};
我还发现这对我有用:
export const mockRepository = jest.fn(() => ({
metadata: {
columns: [],
relations: [],
},
}));
和
const module: TestingModule = await Test.createTestingModule({
providers: [{ provide: getRepositoryToken(Entity), useClass: mockRepository }],
}).compile();