Python正则表达式从OR运算符的非匹配方返回None

Question

我正在尝试创建一个正则表达式，它将从OR的任意一侧返回两个匹配，如下所示：

def parse_description(description):
    regex = r"^(Created by CreateImage\((.*?)\) for (.*?) |Copied for (DestinationAmi) (.*?) from SourceAmi (.*?))"
    matches = re.finditer(regex, description, re.MULTILINE)
    for matchNum, match in enumerate(matches):
        return match.groups()
    return '', ''

用示例字符串：

Copied for DestinationAmi ami-33dfxxx from SourceAmi ami-9dd6xxx for SourceSnapshot snap-02f5xxx. Task created on 1,518,952,817,897.

我遇到的问题是这会返回4个匹配，无，无，ami-33dfxxx，ami-9dd6xxx

在https://pythex.org/尝试了各种各样的事情，我不能让这不能返回4场比赛，尽管据我所知，它不应该。我究竟做错了什么？

Answer 1

感谢建议分支重置的评论，这是我的最终解决方案

import regex
def parse_description(description):
    pattern = r'^(?|Created by CreateImage\((.*?)\) for (.*?) |Copied for (DestinationAmi) (.*?) from SourceAmi )'
    matches = regex.match(pattern,description)
    if matches is None:
        return None
    return(matches.groups())