合并2个独立的foreach循环[关闭]

Question

到目前为止，我已成功从外部站点抓取 2 个元素到我的测试页面： http://mt-cloud.co.uk/nhs/

（请在页面上进行测试搜索以查看结果）

$ch = curl_init('http://www.nhs.uk/service-search/GP/m410ux/Results/4/-2.35167407989502/53.4519462585449/4/0?distance=25');
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1); 
$output = curl_exec($ch);
curl_close($ch);

$document = new DOMDocument;
libxml_use_internal_errors(true);
$document->loadHTML($output);
$document->encoding = 'utf-8';
$xpath = new DOMXPath($document);
$pnames = $xpath->query("//th[@class='fctitle']");
$addresses = $xpath->query("//td[@class='fcdetails fc-first']");

我有 2 个 foreach 循环：

foreach ($pnames as $pname) {
$result1 = $document->saveHTML($pname);
}


foreach ($addresses as $address) {
$result2 = $document->saveHTML($address);
}

$result1 = 全科医生诊所名称 $result2 = 全科医生诊所地址

正如您在测试页上看到的，我的结果 1 和 2 是分开的。我如何获得它们，以便将诊所名称和诊所地址放在一起？

更新（@Tri）

for($i = 0; $i < count($pnames); $i++){
$name= $document->saveHTML($pnames[$i]);
$name=str_replace ('<a href="/Services/', '<a href="http://www.nhs.uk/Services/', $name);
$address = $document->saveHTML($addresses[$i]);

echo $name.'<br>'.$address;
}

仅返回一个结果而不是全部

这是我完整的 php 代码： http://mt-cloud.co.uk/nhs/content/code

我正在尝试抓取的数据图像http://mt-cloud.co.uk/nhs/content/results.png

Answer 1

你的第一个代码没问题，你只需要将你的姓名和地址存储在一个二维数组中，然后循环遍历你的数组。

这部分代码和你的完全一样：

$ch = curl_init('http://www.nhs.uk/service-search/GP/m410ux/Results/4/-2.35167407989502/53.4519462585449/4/0?distance=25');
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1); 
$output = curl_exec($ch);
curl_close($ch);

$document = new DOMDocument;
libxml_use_internal_errors(true);
$document->loadHTML($output);
$document->encoding = 'utf-8';
$xpath = new DOMXPath($document);
$pnames = $xpath->query("//th[@class='fctitle']");
$addresses = $xpath->query("//td[@class='fcdetails fc-first']");

现在我们将创建一个数组：

$results = array();

然后使用循环并将名称和地址成对存储在数组的相同索引中：

$iCnt = 0;
foreach ($pnames as $pname){
    $results[$iCnt]['name'] = $document->saveHTML($pname);
    $iCnt++;
}

$iCnt = 0;
foreach ($addresses as $address){
    $results[$iCnt]['address'] = $document->saveHTML($address);
    $iCnt++;
}

现在我们有一个包含名称和地址对的数组，如果我们循环遍历它，我们可以看到它们在一起：

for($iCnt = 0, $cnt = count($results); $iCnt < $cnt; $iCnt++){
    echo 'Name: '.$results[$iCnt]['name'].'<br>';
    echo 'Address: '.$results[$iCnt]['address'].'<br>';
}

仅此而已。完整的代码如下所示：

<?php
$ch = curl_init('http://www.nhs.uk/service-search/GP/m410ux/Results/4/-2.35167407989502/53.4519462585449/4/0?distance=25');
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1); 
$output = curl_exec($ch);
curl_close($ch);

$document = new DOMDocument;
libxml_use_internal_errors(true);
$document->loadHTML($output);
$document->encoding = 'utf-8';
$xpath = new DOMXPath($document);
$pnames = $xpath->query("//th[@class='fctitle']");
$addresses = $xpath->query("//td[@class='fcdetails fc-first']");

$results = array();

$iCnt = 0;
foreach ($pnames as $pname){
    $results[$iCnt]['name'] = $document->saveHTML($pname);
    $iCnt++;
}

$iCnt = 0;
foreach ($addresses as $address){
    $results[$iCnt]['address'] = $document->saveHTML($address);
    $iCnt++;
}

for($iCnt = 0, $cnt = count($results); $iCnt < $cnt; $iCnt++){
    echo 'Name: '.$results[$iCnt]['name'].'<br>';
    echo 'Address: '.$results[$iCnt]['address'].'<br>';
}
?>

Answer 2

所以不要使用 foreach:

for($i = 0; $i < count($pnames); $i++){
    $name= $document->saveHTML($pnames[$i]);
   $address = $document->saveHTML($addresses[$i]);
   //do something with your result
}

注意：您必须确保地址长度等于pnames