在react应用程序中使用redux更新状态的正确方法是什么?

问题描述 投票:1回答:1

我是新人,现在就做出反应并选择一门课程。我发现状态在使用异步代码更新方面有点令人困惑。在我正在做的教程中,我发誓它说你需要使用thunk来处理使用react / redux更新状态。我对此持怀疑态度,因为我是新人,我并不完全理解这一点。我已经编写了这个react组件和reducer,它工作正常,它将更新博客发送到服务器,接收它,并在收到200响应时更新状态,但我想知道是否有它有什么问题,而不是使用来自http请求的数据更新状态的正确方法。

博客组件

import React, {Component} from 'react';
import axios from '../../http/axios/axios';
import Card from '../../components/UI/Card/Card';
import classes from '../Container.css';
import Button from '../../components/UI/Button/Button';
import * as actionTypes from '../../store/actions/actions';
import { connect } from 'react-redux';


    class Blog extends Component{

        toggleApprovedAndUpdate = (blog) => {
            blog.approved = ! blog.approved
            this.props.updateBlog(blog)
        }

        render() {
            let blogs = this.props.blgs.map((b, index) =>
                    <Card
                        title={b.title}
                        description={b.description}
                        approved={b.approved.toString()}
                        imagePath={b.image}
                        action={this.toggleApprovedAndUpdate.bind(this, b)}
                        key={index} />)
            return(
                <div>
                    <div className={classes.Container}>
                        <Button
                            label={"Get all blogs"}
                            action={this.props.getBlogs}
                        />
                        {blogs}
                    </div>
                </div>
            )
        }
    }


    const mapStateToProps = state => {
        return {blgs: state.blog.blogs};

    };

    const mapDispatchToProps = dispatch => {
        return {
            getBlogs: () => {
                axios.get('/blog')
                    .then((response) => {
                        return dispatch({type: actionTypes.GET_ALL_BLOGS, blogs: response.data})
                    })
            },
            updateBlog: (blog) => {
                axios.put('/blog', blog)
                    .then((response) => {
                        return dispatch({type: actionTypes.UPDATE_BLOG, blogs: response.data})
                    })
            }
        }
    };

    export default connect(mapStateToProps, mapDispatchToProps)(Blog);

博客减速机

import * as actionTypes from './actions';

const initialState = {
    blogs: []
}
const reducer = (state = initialState, action) => {
    switch(action.type){
        case actionTypes.GET_ALL_BLOGS:
            return {
                ...state,
                blogs: action.blogs
            }
        case actionTypes.UPDATE_BLOG:
            return {
                ...state,
                blogs: state.blogs.map((blog) => blog.id === action.blogs.id ? {...blog, approved:action.blogs.approved}: blog )
            }
    }
    return state;
}

export default reducer;
reactjs redux
1个回答
0
投票

我的理解是你可以像在示例中那样调用异步函数,而不需要中间件。像redux-thunk这样的中间件的作用是在调度的动作中添加ID,“排序”它们,避免竞争条件,例如Writing Async Code in redux中描述的竞争条件。

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