在不保留第一级键

Question

我想做的是按名称对条目进行排序，但要保持与条目本身关联的键，所以我想要的是：

$fonts = array(
    0 => ["index" => 0, "name" => "Arial", "path" => "assets/fonts/arial.ttf"],
    1 => ["index" => 1, "name" => "Times", "path" => "assets/fonts/times.ttf"],
    2 => ["index" => 2, "name" => "Roboto", "path" => "assets/fonts/roboto.ttf"],
    3 => ["index" => 3, "name" => "AlexBrush", "path" => "assets/fonts/AlexBrush-Regular.ttf"],
);

the是暴露问题的裸露最小代码（PHP VER +7）：

 $fonts = array(
    3 => ["index" => 3, "name" => "AlexBrush", "path" => "assets/fonts/AlexBrush-Regular.ttf"],
    0 => ["index" => 0, "name" => "Arial", "path" => "assets/fonts/arial.ttf"],
    2 => ["index" => 2, "name" => "Roboto", "path" => "assets/fonts/roboto.ttf"],
    1 => ["index" => 1, "name" => "Times", "path" => "assets/fonts/times.ttf"],
);

我使用

function cmp($a, $b)
{
    return strcmp($a["name"], $b["name"]);
}

$fonts = array(
    0 => ["index" => 0, "name" => "Arial", "path" => "assets/fonts/arial.ttf"],
    1 => ["index" => 1, "name" => "Times", "path" => "assets/fonts/times.ttf"],
    2 => ["index" => 2, "name" => "Roboto", "path" => "assets/fonts/roboto.ttf"],
    3 => ["index" => 3, "name" => "AlexBrush", "path" => "assets/fonts/AlexBrush-Regular.ttf"],
);

uasort($fonts, "cmp");

for($i = 0; $i < 4; $i++)
{
    echo "<br/>".$fonts[$i]["name"];
}

在对数组进行排序时应该保持关联的密钥。不幸的是，如果我打印了数组，我会得到相同的顺序，也就是说：

uasort()

do

Arial
Times
Roboto
AlexBrush

sort

Answer 1

喜欢这种方式，并使用

foreach()

<?php

$fonts = array(
    0 => ["index" => 0, "name" => "Arial", "path" => "assets/fonts/arial.ttf"],
    1 => ["index" => 1, "name" => "Times", "path" => "assets/fonts/times.ttf"],
    2 => ["index" => 2, "name" => "Roboto", "path" => "assets/fonts/roboto.ttf"],
    3 => ["index" => 3, "name" => "AlexBrush", "path" => "assets/fonts/AlexBrush-Regular.ttf"],
);

uasort($fonts, function($a, $b) {
    return strcmp($a['name'], $b['name']);
});

print_r($fonts);

foreach($fonts as $font){
 echo $font["name"].PHP_EOL;
}

?>

Edit：

基于OP的评论，

 $indexed_array = array_column($fonts,'name','index'); // array column map name by index
 print_r($indexed_array); 
 echo $indexed_array[3];

demo：

https：//3v4l.org/w7boh

您正在使用...

for($i = 0; $i < 4; $i++)
{
    echo "<br/>".$fonts[$i]["name"];
}

Answer 2

如果您使用...

print_r($fonts); 你会看到他们已经被分类并得到了...

Array
(
    [3] => Array
        (
            [index] => 3
            [name] => AlexBrush
            [path] => assets/fonts/AlexBrush-Regular.ttf
        )

    [0] => Array
        (
            [index] => 0
            [name] => Arial
            [path] => assets/fonts/arial.ttf
        )

    [2] => Array
        (
            [index] => 2
            [name] => Roboto
            [path] => assets/fonts/roboto.ttf
        )

    [1] => Array
        (
            [index] => 1
            [name] => Times
            [path] => assets/fonts/times.ttf
        )

)

或L. Faros在评论中指出的那样，如果您使用的话...

foreach ( $fonts as $font ) {
    echo "<br/>".$font["name"];
}

你会得到

<br/>AlexBrush<br/>Arial<br/>Roboto<br/>Times

您可以使用array_column进行数组关联，然后与ksort（键sort）进行排序。

$fonts = array_column($fonts, null, "name");
ksort($fonts);
$fonts = array_values($fonts);
var_dump($fonts);

输出：

array(4) {
  [0]=>
  array(3) {
    ["index"]=>
    int(3)
    ["name"]=>
    string(9) "AlexBrush"
    ["path"]=>
    string(34) "assets/fonts/AlexBrush-Regular.ttf"
  }
  [1]=>
  array(3) {
    ["index"]=>
    int(0)
    ["name"]=>
    string(5) "Arial"
    ["path"]=>
    string(22) "assets/fonts/arial.ttf"
  }
  [2]=>
  array(3) {
    ["index"]=>
    int(2)
    ["name"]=>
    string(6) "Roboto"
    ["path"]=>
    string(23) "assets/fonts/roboto.ttf"
  }
  [3]=>
  array(3) {
    ["index"]=>
    int(1)
    ["name"]=>
    string(5) "Times"
    ["path"]=>
    string(22) "assets/fonts/times.ttf"
  }
}

Answer 3

https：//3v4l.org/pjxfp

我看到您要求如何获得索引3名称。

在这种情况下，再次使用array_column将其在索引上进行关联。 https：//3v4l.org/nctjf

$fonts = array_column($fonts, null, "name");
ksort($fonts);
$fonts = array_column($fonts, null, "index");

echo $fonts[3]["name"]; //AlexBrush

---

如果您要继续使用

for()

，则实际上需要重新索引第一级键 - 这没什么大不了的，因为您仍然保存在

index

元素中的原始数字ID。 与该逻辑保持一致，我可以推荐两个不同的单线。

array_multisort(array_column($fonts, 'name'), $fonts);

Answer 4

usort($fonts, function($a, $b){return $a['name'] <=> $b['name'];});

demo