给定两个 Json 列表，如何删除 JSon 中为 null 且不存在于名为 parsedXmlChild 的 Json 列表中的字段并将其存储在新列表中？

Question

parsedJsonChildData (original data): [{date=null, feeForPerformance=null, feeFrequency=5}, {date=12-25-2024, feeForPerformance=23, feeFrequency=1}, {date=12-03-2025, feeForPerformance=1, feeFrequency=5}]

parsedXmlChildData (original data): [{date=null, feeFrequency=5}, {date=12-25-2024, feeForPerformance=23, feeFrequency=1}, {date=12-03-2025, feeForPerformance=1, feeFrequency=5}]

在

parsedJsonChildData

的第一个索引中，应删除

feeForPerformance=null

，因为它在

parsedXmlChildData

中不可用，标准是如果该字段在 parsedJsonChildData 中为 Null 并且不存在于 parsedXmlChildData 中，则应从 parsedJsonChildData 中删除它

我尝试编写代码，但仍然得到相同的输出

public static List<Map<String, Object>> cleanJsonData(List<Map<String, Object>> parsedJsonChildData, List<Map<String, Object>> parsedXmlChildData) {
    List<Map<String, Object>> modifiedParsedJsonChildData = new ArrayList<>();

    // Iterate over each index in the JSON and XML lists
    for (int i = 0; i < parsedJsonChildData.size(); i++) {
        Map<String, Object> jsonObject = parsedJsonChildData.get(i);
        Map<String, Object> xmlObject = parsedXmlChildData.get(i);

        // Create a new map to hold the cleaned JSON object
        Map<String, Object> cleanedJsonObject = new HashMap<>(jsonObject);

        // Iterate over the entries in the JSON object
        Iterator<Map.Entry<String, Object>> iterator = cleanedJsonObject.entrySet().iterator();
        while (iterator.hasNext()) {
            Map.Entry<String, Object> entry = iterator.next();
            String jsonField = entry.getKey();
            Object jsonValue = entry.getValue();

            // If the field is null in JSON and is missing in XML, remove it from JSON
            if (jsonValue == null && !xmlObject.containsKey(jsonField)) {
                iterator.remove(); // Remove the field from the copied JSON
                System.out.println("Removed field from JSON: " + jsonField); // Log the removal
            }
        }

        // Add the cleaned JSON object to the modified list
        modifiedParsedJsonChildData.add(cleanedJsonObject);
    }

    return modifiedParsedJsonChildData; // Return the cleaned JSON data only
}

输出：

modifiedParsedJsonChildData (after cleaning): [{date=null, feeForPerformance=null, feeFrequency=5}, {date=12-25-2024, feeForPerformance=23, feeFrequency=1}, {date=12-03-2025, feeForPerformance=1, feeFrequency=5}] 

还是一样

Answer 1

我找到了一个可行的解决方案

公共静态列表> cleanJsonData（列表> parsedJsonChildData，列表> parsedXmlChildData）{ 列表> moddedParsedJsonChildData = new ArrayList<>();

    for (int i = 0; i < parsedJsonChildData.size(); i++) {
        Map<String, Object> jsonItem = parsedJsonChildData.get(i);
        Map<String, Object> xmlItem = parsedXmlChildData.get(i);

        Map<String, Object> filteredItem = new HashMap<>();
        for (Map.Entry<String, Object> entry : jsonItem.entrySet()) {
            String key = entry.getKey();
            Object value = entry.getValue();


            if ((value != null && !value.toString().isEmpty()) || xmlItem.containsKey(key)) {
                filteredItem.put(key, value);
            }
        }
        modifiedParsedJsonChildData.add(filteredItem);
    }

    return modifiedParsedJsonChildData;


}