如何在NestJs + TypeOrm(后端)中调用存储过程

问题描述 投票:0回答:1

我在oracle数据库中存储过程,我想在NestJs中调用它。如何在NestJs中调用存储过程?

这是我的存储过程

PROCEDURE pipeline_critical (
        i_main_company IN NUMBER,
        o_value OUT NUMBER
   ) AS
   BEGIN
    SELECT COUNT(A.PIPELINE_ID) AS IGNORED_PIPELINE 
    INTO o_value
    FROM T_PIPELINE A
    LEFT JOIN T_PIPELINE_PRODUCT P ON P.PIPELINE_ID = A.PIPELINE_ID
    WHERE 
        1 = ( CASE WHEN
                i_main_company <> 3
                AND A.MAIN_COMPANY_ID = i_main_company
                AND TO_CHAR(A.EST_DELIVERY,'YYYY') >= TO_CHAR(SYSDATE,'YYYY') - 1
                AND A.PIPELINE_STATUS_ID IN (1,2,3)
                AND TO_CHAR(ADD_MONTHS(A.UPDATE_DATE,3),'YYYYMM') < TO_CHAR(SYSDATE,'YYYYMM')
                AND P.PAID_DATE IS NULL THEN 1
            WHEN
                i_main_company = 3
                AND TO_CHAR(A.EST_DELIVERY,'YYYY') >= TO_CHAR(SYSDATE,'YYYY') - 1
                AND A.PIPELINE_STATUS_ID IN (1,2,3)
                AND TO_CHAR(ADD_MONTHS(A.UPDATE_DATE,3),'YYYYMM') < TO_CHAR(SYSDATE,'YYYYMM')
                AND P.PAID_DATE IS NULL THEN 1
            END
        );
   END pipeline_critical;
nestjs
1个回答
1
投票

我正在迁移Javascript / sequealize Backend,我正在测试我的需求。这是一个对我有用的简单示例:

这是存储过程

CREATE PROCEDURE sp_prueba
@email varchar(100)
AS
BEGIN
    SET NOCOUNT ON;
    select * from tbusua where emai_usua=@email
END

在NESTJS - 控制器

import { Controller, Get, Param } from '@nestjs/common';
import { UsuariosService } from './usuarios.service';
import { async } from 'rxjs/internal/scheduler/async';
import { Usuario } from './usuarios.entity';


@Controller('Usuarios')
export class UsuariosController {
constructor(private readonly UsuariosService: UsuariosService) { }
@Get('/:email')
async find(@Param('email') email): Promise <Usuario[]>{
    return await this.UsuariosService.find(email);
}

}

并在NESTJS - TypeORM后端服务中

import { Injectable } from '@nestjs/common';
import { InjectRepository } from '@nestjs/typeorm';
import { Usuario } from './usuarios.entity';
import { Repository, Db, EntityManager } from 'typeorm';

@Injectable()
export class UsuariosService {
constructor(
    @InjectRepository(Usuario)
    private readonly usuariosRepository: Repository<Usuario>) { }
 async find(email: string): Promise<Usuario[]>{
    return await this.usuariosRepository.query("sp_prueba @email='"+email +"'");
 }
}

这项工作对我来说

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