将值传递给 PHP 脚本！获取还是发布？

Question

<div class="bg-img">
    <form method="POST" action="https://click2call.aosystemsgroup.com/wcb.php">
        <div class="input-container">
            <span class="material-icons icon" style="font-size: 14px; background: rgb(22,58,130); background: linear-gradient(0deg, rgba(22,58,130,1) 30%, rgba(112,172,222,1) 70%)">call</span>
            <input type="text" class="input-field" name="num" placeholder="Phone Number:" id="webcallbackinput" onkeydown="javascript:backspacerDOWN(this,event);" onkeyup="javascript:backspacerUP(this,event);" value=""/>
            <input type="hidden" id="dest" value="http://click2call.aosystemsgroup.com/wcb.php"/>
            <input type="hidden" id="i" value="1"/>
            <input type="image" height="37" src="images/c2c_button.png" width="145" style="  position: relative; left: 8px; top: 145px" alt="submit"/>
        </div>
    </form>

朋友们，我需要将两个值传递给位于远程服务器的 php 脚本。只是为了确保我理解这一点：

我只想传递：1.目标位置（dest），2.“num”（电话号码）xxxxxxxxxx和ID（可能会在sql条目中命中一行。

我这样做正确吗？

Answer 1

<div class="bg-img">
<form method="POST" action="https://click2call.aosystemsgroup.com/wcb.php">
<div class="input-container">
    <span class="material-icons icon" style="font-size: 14px; background: rgb(22,58,130); background: linear-gradient(0deg, rgba(22,58,130,1) 30%, rgba(112,172,222,1) 70%)">call</span>
    <input type="text" class="input-field" name="num" placeholder="Phone Number:" id="webcallbackinput" onkeydown="javascript:backspacerDOWN(this,event);" onkeyup="javascript:backspacerUP(this,event);" value=""/>
    <input type="hidden" id="dest" value="http://click2call.aosystemsgroup.com/wcb.php"/>
    <input type="hidden" id="i" value="1"/>
    <input type="image" height="37" src="images/c2c_button.png" width="145" style="  position: relative; left: 8px; top: 145px" alt="submit"/>
</div>
</form>