我有许多URL的列表,我想为其提取特定元素,每个URL中的查询选择器都相同。
例如,在Chrome浏览器中打开了网址“ http://www.nationalregisterofhistoricplaces.com/al/autauga/state.html”然后运行此命令
document.querySelector("body > div:nth-child(7) > div.listheader")
我在Chrome浏览器控制台中获得了所需内容的打印件(如果我应该尝试使用其他工具中的javascript脚本,请告诉我哪个)]
[我是Java语言的新手,我正在尝试,我想从URL_1中提取div元素并将其保存到out.html,然后从URL_2中提取div直到URL_N并追加到先前的div下面,依此类推。
到目前为止,我已经尝试了以下代码,但是它仅在新选项卡中打开第一个URL,并且不打印其div。
var urls = [ "http://www.nationalregisterofhistoricplaces.com/al/autauga/state.html", "http://www.nationalregisterofhistoricplaces.com/al/barbour/state.html", "http://www.nationalregisterofhistoricplaces.com/ca/fresno/state.html" ]; for (i = 0; i < urls.length; i++) { window.open(urls[i]) document.querySelector("body > div:nth-child(7) > div.listheader") };
我的目标是合并每个URL的div并将它们保存在看起来像这样的out.html中:
<!-- div from URL_1 --> <div class="listheader"> <img src="/nr-images/flag.gif" width="33" height="28"> <div class="listname">Bell House <span class="added">(added 1999 - - #99000150)</span> </div> <div class="listaka">Also known as Biggs House</div> <div class="listaddress">550 Upper Kingston Rd. , Prattville </div> </div> <!-- div from URL_2 --> <div class="listheader"> <img src="/nr-images/flag.gif" width="33" height="28"> <div class="listname">Bray-Barron House <span class="added">(added 1971 - - #71000093)</span> </div> <div class="listaddress">N. Eufaula Ave. , Eufaula </div> </div> <!-- div from URL_3 --> <div class="listheader"> <img src="/nr-images/flag.gif" width="33" height="28"> <div class="listname">Bank of Italy <span class="added">(added 1982 - - #82000963)</span> </div> <div class="listaka">Also known as Bank of America on Fulton Mall</div> <div class="listaddress">1015 Fulton Mall , Fresno </div> </div>
我该怎么做?预先感谢。
我有许多URL的列表,我要为其提取特定元素,每个URL中具有相同的查询选择器。例如,在Chrome中打开URL“ http:// www ....