带有硬包装像素限制的Java Swing中的单词换行

Question

我在摆动环境中在java中实现自动换行时遇到问题。我有像素的硬限制，我不能过去。我觉得我很亲密，因为我找到了一个包装的解决方案，但它让最后一个字超过限制，然后再转到下一行。

'ni'是一个缓冲的图像，这一切都被吸引到了。

'theSettings'自定义类，包含文本的变量。

'theText'是需要包装的字符串。

这是传递给方法的内容：

FontMetrics fm = ni.createGraphics().getFontMetrics(theSettings.getFont());
//Get pixel width of string and divide by # of characters in string to get estimated width of 1 character
int charPixelWidth = fm.stringWidth(theText) / theText.length();
int charWrap = theSettings.getPixelsTillWrap() / charPixelWidth;
List<String> textList = testWordWrap(theText, charWrap);

我正在使用这种方法来测试：

//Custom String Wrapper as StringUtils.wrap keeps cutting words in half
public static List<String> testWordWrap(String wrapMe, int wrapInChar) {
    StringBuilder sb = new StringBuilder(wrapMe);

    int count = 0;
    while((count = sb.indexOf(" ", count + wrapInChar)) != -1) {
        sb.replace(count, count + 1, "\n");
    }

    String toArray = sb.toString();
    String[] returnArray = toArray.split("\\n");

    ArrayList<String> returnList = new ArrayList<String>();
    for(String s : returnArray) {
        returnList.add(s);
    }

    return returnList;
}

使用示例：

我还替换了文本中间的图像，但图像的大小正是它所替换的文本的大小;所以这应该不是问题。蓝线是边界框，显示包裹应该结束的位置。它表明文本继续绘制。我需要函数将'succeeded'包装到下一行;因为在任何情况下包裹都无法运行。

编辑：图像的数组运行为.toString();

[决议：+ | FT |如果你成功了，并匹配| EA |]

[任何：+ | MT |当你获得任何数字时，| QT |]

Answer 1

我能够找到答案。我将字符串拆分为空格，然后尝试一次添加一个字。如果太长，请跳到下一行。在这里，它被评论为帮助其他人解决同样的问题。干杯!

//@Author Hawox
//split string at spaces
//for loop checking to see if adding that next word moves it over the limit, if so go to next line; repeat
public static List<String> wordWrapCustom(String wrapMe, FontMetrics fm, int wrapInPixels){
    //Cut the string into bits at the spaces
    String[] split = wrapMe.split(" ");

    ArrayList<String> lines = new ArrayList<String>(); //we will return this, each item is a line
    String currentLine = ""; //All contents of the currentline

    for(String s : split) {
        //Try to add the next string
        if( fm.stringWidth(currentLine + " " + s) >= wrapInPixels ) {
            //Too big
            if(currentLine != "") { //If it is still bigger with an empty string, still add at least 1 word
                lines.add(currentLine); //Add the line without this string 
                currentLine = s; //Start next line with this string in it
                continue;
            }
        }
        //Still have room, or a single word that is too big
        //add a space if not the first word
        if(currentLine != "")
            currentLine = currentLine + " ";

        //Append string to line
        currentLine = currentLine + s;
    }
    //The last line still may need to get added
    if(currentLine != "") //<- Should not get called, but just in case
        lines.add(currentLine);

    return lines;
}