PHP，基于循环迭代进行mysql更新

Question

我有一个PHP文件，可以达到某个点，但我需要一些帮助在循环上做一个MySQl插入。

以下执行SELECT，然后存储order_status为'S'的所有记录的订单ID。这完美地工作，打印每个适当的订单ID。

然后我将那些受影响的ORder ID推送到一个数组，以便我可以保存它们以用于各种功能。

    //Query for checking all records in order_status
    $orderCheck = "
            SELECT 
                order_id,
                order_status
            FROM order_status
    ";

    $result = mysqli_query($mysqlConn, $orderCheck);
    $order_ids = array();


    //loop results to gather order IDs and store them
    while ($row = mysqli_fetch_array($result))
        {
        $order_id = $row['order_id'];
        if ($row['order_status'] == "S")
            {
            array_push($order_ids, $order_id);
            }
        }

    //print_r($order_ids);
    //This does indeed print the correct order Ids

以下部分需要一些工作，我不太清楚这里要做什么。我正在迭代和预测那些迭代我有更新，但我担心更新的语法不正确，我不知道我是否需要在这里做另一个数组。

    //This is where I'm stuck//
    //Now I need to iterate through those orderIDs and update is_placement to 1, since it's a bit column, and udpate date_updated to curdate()

    for($i=0; $i<count($order_id); $i++) {

        $sql = "UPDATE order_status SET is_placement = '1' and date_updated = curdate() WHERE order_id = '$order_id'"; //I don't believe this syntax is correct    
    }

基本上，我需要为先前存储的$ order id数组的每次迭代执行mysql更新。

任何想法或建议/指导都非常感谢。

更新：

数组的输出：

[287] => 11605809
[288] => 11605817
[289] => 11605825
[290] => 11605863
[291] => 11605869
[292] => 11605870
[293] => 11605875
[294] => 12605471
[295] => 12605643
[296] => 12605715
[297] => 12605778
[298] => 12605817

Answer 1

向MySQL询问所有订单是没有意义的，然后手动选择状态为S.

更好：

// Select only orders in status S.
$orderCheck = "SELECT order_id FROM order_status WHERE order_status = 'S';"

$result = mysqli_query($mysqlConn, $orderCheck);
$order_ids = array();

while ($row = mysqli_fetch_array($result)) {
    $order_ids[] = $row['order_id'];
}

现在您要更新这些记录。如果你一个接一个地做，你可以：

foreach ($order_ids as $order_id) {
    $sql = "UPDATE order_status SET is_placement = 1, date_updated = DATE(NOW()) WHERE order_id = '$order_id';";
    // EXECUTE
}

更快的方法是（我不添加引号，假设订单ID是数字，但如果它们不是事情变得有点复杂）将所有订单ID放在一起并使用IN语法：

$bunchOfOrders = implode(',', $order_ids);

$singleQuery = "UPDATE order_status SET is_placement = 1, date_updated = DATE(NOW()) WHERE order_id IN ({$bunchOfOrders})";

但你也可以在MySQL中完成所有这些：

$orderUpdate = "UPDATE order_status SET is_placement = 1, date_updated = NOW() WHERE order_status = 'S';"

$result = mysqli_query($mysqlConn, $orderUpdate);

由于上述内容不会从S更改订单状态，因此您还可以运行$ orderCheck并检索所涉及的订单ID（如有必要）。

为了确保不会发生任何不幸事件，我还会将整个操作包装在事务中。

Another twist

如果我们必须根据某些条件运行一系列不同的修改（当然是互斥的），该怎么办？

我们可以用地图做这个，只要我们使用确定性函数并且没有修改就会改变下面的条件（所以，你不能在任何“食谱”中改变order_status，否则它会影响后面的那些）：

$todo = array(
    "order_status='S'"    => "is_placement = 1, date_updated = DATE(NOW())",
    "order_status='K'"    => "is_placement = 2, date_updated = DATE(NOW())",
    "order_status='L'"    => "owner='NOBODY'",
    "o_s='X' AND a=12"    => "note='A random condition'",
    // We can also supply a "what to do if none of the above":
    "DEFAULT"             => "note='THIS RECORD DOES NOT MATCH'",
);
$else = array();
foreach ($todo as $when => $then) {
    if ('DEFAULT' !== $when) {
        $else[] = "({$when})";
    } else {
        // "ELSE" means when no other condition is matched.
        // i.e. NOT when1 AND NOT when2 AND NOT when3...
        // which is equivalent to NOT ( when1 OR when2 ... )
        $when = "NOT (" . implode(' OR ', $else) . ")";
    }
    $sql = "UPDATE order_status SET {$then} WHERE {$when};";
    // Execute $sql.
}

Answer 2

您可以使用的是foreach()声明：

foreach($order_ids AS $order_id) {
    $sql = "UPDATE order_status SET is_placement = '1', date_updated = curdate() WHERE order_id = $order_id";
    // execute the query here
} 

当您使用表格中包含的数据时，您应该考虑学习prepared语句MySQLi

Answer 3

我会更改初始查询，因此您不必多次循环任何内容。

试试这个：

    //Query for checking all records in order_status
    $orderCheck = "
        SELECT 
        order_id,
        order_status
        FROM order_status
        WHERE order_status = 'S'
    ";

$result = mysqli_query($mysqlConn, $orderCheck);
$order_ids = array();

//loop results to gather order IDs and store them
while ($row = mysqli_fetch_row($result))
{
    $sql = "UPDATE order_status SET is_placement = '1' and date_updated = curdate() WHERE order_id = '$row[0]'";
}