尝试从 swift URLSession 更新数据库返回 503

Question

我正在更新数据库中的 2 个表。一个有效 HTTPURLResponse 200。另一个失败响应 503。

不快速编码的人。所有参数值均已设置且有效。显示我的 POST 方法，但 GET 也失败并出现 503 错误。

private func post() async throws {
    let rcid = UserDefaults.standard.value(forKey: DefaultKey.rcID.rawValue) as? String ?? "NOT SET"
    
    guard let url = URL(string: "https://example.com/folder/subfolder/insertUserIntoDBPOST.php") else {
        throw URLError(.badURL)
    }
    
    var request = URLRequest(url: url)
    request.httpMethod = "POST"
    
    let parameters = [
        URLQueryItem(name: "Line", value: selectedLine),
        URLQueryItem(name: "Depot", value: selectedDepot),
        URLQueryItem(name: "RCID", value: rcid),
        URLQueryItem(name: "RemainingFreeLaunches", value: String(remainingFreeLaunches)),
        URLQueryItem(name: "SubscriptionStatus", value: subscriptionDuration.rawValue)
    ]
    
    let parameterString = parameters.map { "\($0.name)=\($0.value ?? "")" }.joined(separator: "&")
    request.httpBody = parameterString.data(using: .utf8)
    
    do {
        let (data, response) = try await URLSession.shared.data(for: request)
        
        guard let httpResponse = response as? HTTPURLResponse else {
            throw URLError(.badServerResponse)
        }
        
        if httpResponse.statusCode == 200 {
            // do something with a successful update
        } else {
            /// throw the error (for eg 503) 
            throw URLError(.badServerResponse)
        }
    } catch {
        throw error
    }
}

服务器端PHP

<?php

require_once("../../includes/connection_auth.php");

if ($connection->connect_error) {
    die("Connection failed: " . $connection->connect_error);
}

if (isset($_POST['Line'], $_POST['Depot'], $_POST['RCID'], $_POST['RemainingFreeLaunches'], $_POST['SubscriptionStatus'])) {
    $line = mysqli_real_escape_string($connection, $_POST['Line']);
    $depot = mysqli_real_escape_string($connection, $_POST['Depot']);
    $rcid = mysqli_real_escape_string($connection, $_POST['RCID']);
    $remainingFreeLaunches = (int) $_POST['RemainingFreeLaunches']; 
    $subscriptionStatus = mysqli_real_escape_string($connection, $_POST['SubscriptionStatus']);
} else {
   die("Missing POST data. Please ensure all required fields are provided.");
}

$insertQuery = "INSERT INTO usersTable (Line, Depot, RCID, RemainingFreeLaunches, SubscriptionStatus) 
                VALUES (?, ?, ?, ?, ?) 
                ON DUPLICATE KEY UPDATE 
                Line = VALUES(Line), Depot = VALUES(Depot), RemainingFreeLaunches = VALUES(RemainingFreeLaunches), SubscriptionStatus = VALUES(SubscriptionStatus);";

$stmt = mysqli_prepare($connection, $insertQuery);

if ($stmt === false) {
    die("Error preparing query: " . mysqli_error($connection));
}

mysqli_stmt_bind_param($stmt, "sssis", $line, $depot, $rcid,$remainingFreeLaunches, $subscriptionStatus);

if (mysqli_stmt_execute($stmt)) {
    echo "Record inserted/updated successfully";
} else {
    echo "Error: " . mysqli_stmt_error($stmt);
}

mysqli_stmt_close($stmt);
$connection->close();
?>

Answer 1

已解决：该问题是由于语法与 MariaDB 不兼容所致。

改变了

$insertQuery = "INSERT INTO usersTable (Line, Depot, RCID, RemainingFreeLaunches, SubscriptionStatus) 
                VALUES (?, ?, ?, ?, ?) 
                ON DUPLICATE KEY UPDATE 
                Line = VALUES(Line), Depot = VALUES(Depot), RemainingFreeLaunches = VALUES(RemainingFreeLaunches), SubscriptionStatus = VALUES(SubscriptionStatus);";

到

$insertQuery = "INSERT INTO usersTable (Line, Depot, RCID, RemainingFreeLaunches, SubscriptionStatus) 
                VALUES (?, ?, ?, ?, ?) 
                ON DUPLICATE KEY UPDATE 
                Line = ?, Depot = ?, RemainingFreeLaunches = ?, SubscriptionStatus = ?;";