将 JSON 对象转换为查询字符串以附加到 GET URL 的最佳方法是什么? POST 很简单,可以由我的 Web API 后端读取。
{Name: 'Mike' } = ?Name=Mike
private static string MakeRequest(HttpWebRequest req, string data)
{
try
{
if (req.Method == Verbs.POST.ToString() || req.Method == Verbs.PUT.ToString() || req.Method == Verbs.DELETE.ToString())
{
var encodedData = Encoding.UTF8.GetBytes(data);
req.ContentLength = encodedData.Length;
req.ContentType = "application/json";
req.GetRequestStream().Write(encodedData, 0, encodedData.Length);
}
using (var response = req.GetResponse() as HttpWebResponse)
using (var reader = new StreamReader(response.GetResponseStream()))
{
return reader.ReadToEnd();
}
}
catch (WebException we)
{
if(we.Response == null)
{
return JsonConvert.SerializeObject(new { Errors = new List<ApiError> { new ApiError(11, "API is currently unavailable") }});
}
using (var response = we.Response as HttpWebResponse)
using (var reader = new StreamReader(response.GetResponseStream()))
{
return reader.ReadToEnd();
}
}
}
如果 json 对象像您的示例一样是扁平的,那么
string json = @"{
""name"": ""charlie"",
""num"": 123
}";
var jObj = (JObject)JsonConvert.DeserializeObject(json);
var query = String.Join("&",
jObj.Children().Cast<JProperty>()
.Select(jp=>jp.Name + "=" + HttpUtility.UrlEncode(jp.Value.ToString())));
查询将是
name=charlie&num=123
我让这段代码在.Net Core中运行:
public static string JsonToQuery(this string jsonQuery)
{
string str = "?";
str += jsonQuery.Replace(":", "=").Replace("{","").
Replace("}", "").Replace(",","&").
Replace("\"", "");
return str;
}
示例:
var _baseURI = "http://www.example.com/";
var endPoint = "myendpoint";
ExampleObjectModel requestModel = new ExampleObjectModel();
var requestModelJson = JsonConvert.SerializeObject(requestModel);
var url = string.Format("{0}{1}{2}", _baseURI, endPoint, requestModelJson.JsonToQuery());
尝试这个,深入地工作所有对象
public static class ExtensionMethods
{
public static string GetQueryString(this object obj, string prefix = "")
{
var query = "";
try
{
var vQueryString = (JsonConvert.SerializeObject(obj));
var jObj = (JObject)JsonConvert.DeserializeObject(vQueryString);
query = String.Join("&",
jObj.Children().Cast<JProperty>()
.Select(jp =>
{
if (jp.Value.Type == JTokenType.Array)
{
var count = 0;
var arrValue = String.Join("&", jp.Value.ToList().Select<JToken, string>(p =>
{
var tmp = JsonConvert.DeserializeObject(p.ToString()).GetQueryString(jp.Name + HttpUtility.UrlEncode("[") + count++ + HttpUtility.UrlEncode("]"));
return tmp;
}));
return arrValue;
}
else
return (prefix.Length > 0 ? prefix + HttpUtility.UrlEncode("[") + jp.Name + HttpUtility.UrlEncode("]") : jp.Name) + "=" + HttpUtility.UrlEncode(jp.Value.ToString());
}
)) ?? "";
}
catch (Exception ex)
{
}
return query;
}
}
使用:SomeObject.GetQueryString();
如果你的对象(实体)有一个像这个实体的孩子:
public class Parent
{
public Child childs { get; set; } = new Child();
public int PageIndex { get; set; }
public int? PageSize { get; set; }
}
public class Child
{
public int Id { get; set; }
public string Name { get; set; }
}
您可以使用此代码来构建查询: 首先将实体模型转换为 JObject 并调用这个方法:
public static string GetQueryString(this JObject jObj)
{
return String.Join("&",
jObj.Children().Cast<JProperty>()
.Select(jp =>
{
if (jp.Value.Type == JTokenType.Object)
{
var arrValue = String.Join("&",
jObj.Values().Children().Cast<JProperty>()
.Select(jp => jp.Path + "=" + HttpUtility.UrlEncode(jp.Value.ToString())));
return arrValue;
}
else
{
var arrValue = String.Join("&", jp.Name + "=" + HttpUtility.UrlEncode(jp.Value.ToString()));
return arrValue;
}
}
)) ?? "";
}
您可以获得这样的查询字符串:
childs.Id=1&childs.Name="Test"&PageIndex=1&PageSize=1