Openpyxl-没看到价格

Question

我正在编写一个程序，用于在工作簿中搜索零件编号。如果找到指定的部件号，则在该行上进行迭代以找到您指定的部件价格值，并将两者都替换为替换值。

但是我的代码找不到价格

import openpyxl
import os
from datetime import datetime


DIRECTORY = os.path.dirname(os.path.realpath(__file__))
extentions = (".xlsx", ".xlsm", ".xltx", ".xltm")

target = input("\033[1m\033[96mPart number: \033[0m")
target_replacement = input("\033[1m\033[96mReplace with: \033[0m")

price = input("\033[1m\033[96mPrice: \033[0m")
price_replacement = input("\033[1m\033[96mReplace with: \033[0m")


for (root, dirs, files) in os.walk(DIRECTORY):
    for file in files:
        if (file.endswith(extentions)):
            path = os.path.join(root, file)
            print(
                "\033[1m\033[96mOpening:\033[0m \033[1m\033[93m{0}\033[0m".format(file))
            wb = openpyxl.load_workbook(path, data_only=True)
            ws = wb.active
            target_in_wb = False
            for ws in wb.worksheets:
                for row in ws.iter_rows():
                    target_in_row = False
                    price_in_row = False
                    for cell in row:
                        if (cell.value == target):
                            print("\033[1m\033[92mTARGET STRING FOUND\033[0m")
                            print("\033[1m\033[96mReplacing\033[0m \033[1m\033[93m{0}\033[0m with \033[1m\033[93m{1}\033[0m on row \033[1m\033[93m{2}\033[0m".format(
                                target, target_replacement, ws._current_row))
                            cell.value = target_replacement
                            target_in_wb = True
                            for cell in row:
                                target_in_row = False

                                if (cell.value == price):
                                    print(
                                        "\033[1m\033[92mPRICE STRING FOUND\033[0m")
                                    print("\033[1m\033[96mReplacing\033[0m \033[1m\033[93m{0}\033[0m with \033[1m\033[93m{1}\033[0m on row \033[1m\033[93m{2}\033[0m".format(
                                        price, price_replacement, ws._current_row))
                                    cell.value = price_replacement
                                    price_in_row = True

            if (target_in_row == False):
                print(
                    "\033[1m\033[91mPrice string not found\033[0m")

            if (target_in_wb == False):
                print("\033[1m\033[91mPart not found\033[0m")

                print(
                    "\033[1m\033[96mSaving:\033[0m \033[1m\033[93m{}\033[0m at \033[1m\033[96m{}\033[0m\n".format(file, datetime.now()))
                wb.save(file)

print("\033[95m[\033[0m\033[96m*\033[0m\033[95m]\033[0m \033[1m\033[96mDone\033[0m")

Answer 1

我能够通过更改来解决此问题：

price = input("\033[1m\033[96mPrice: \033[0m")
price_replacement = input("\033[1m\033[96mReplace with: \033[0m")

至：

price = float(input("\033[1m\033[96mPrice: \033[0m"))
price_replacement = float(input("\033[1m\033[96mReplace with: \033[0m"))

）