Tkinter不会完成gui的中间更新，除非它完成剩余的处理

Question

我是编程和python的新手，请找到示例代码，这是一个井字游戏，我希望gui在开始处理下一帧之前更新我的“ marking x”帧。

我不知道如何使它起作用，

try:
    import tkinter as tk
except:
    import Tkinter as tk
import time as t
import random as r

data_list = ['a1', 'a2', 'a3', 'a4', 'a5', 'a6', 'a7', 'a8', 'a9']
used_list = ['a1', 'a2', 'a3', 'a4', 'a5', 'a6', 'a7', 'a8', 'a9']
color = ['green yellow', 'yellow', 'green yellow', 'yellow',
         'green yellow', 'yellow', 'green yellow', 'yellow', 'green yellow']
row_col = [(0, 0), (0, 1), (0, 2), (1, 0), (1, 1), (1, 2), (2, 0), (2, 1), (2, 2)]
unused = list

mw = tk.Tk()
mw.geometry("300x300+50+50")

for i in range(3):
    mw.columnconfigure(i, weight=10)
    mw.rowconfigure(i, weight=10)

for j in range(9):
    data_list[j] = tk.Frame(mw)
    data_list[j].grid(row=row_col[j][0], column=row_col[j][1])
    data_list[j].config(background=color[j], width=100, height=100)
    data_list[j].rowconfigure(0, minsize=100)
    data_list[j].columnconfigure(0, minsize=100)
    tk.Button(data_list[j], background=color[j], border=1, command=lambda x=j: cross_mark(data_list[x])).grid(row=0, column=0, columnspan=1, rowspan=1, sticky='nsew')


def cross_mark(blk):
    tk.Button(blk, background='orange red', border=4, text='X', font='30').grid(row=0, column=0, columnspan=1, rowspan=1, sticky='nsew')
    comp_mark(blk)


def comp_mark(used):
    blk = r.choice(data_list)
    if blk == used:
        while blk == used:
            blk = r.choice(data_list)
    t.sleep(5)
    tk.Button(blk, background='RoyalBlue1', border=4, text='X', font='30').grid(row=0, column=0, columnspan=1, rowspan=1, sticky='nsew')
mw.mainloop()

请运行上面的代码，看看是否可以解决我的问题

Answer 1

使用tkinter提供的after方法在一定时间后处理某个功能/回调事件。使用tkinter时，永远无法使用time.sleep，因为tkinter本身处于持续的等待状态（即，它正在等待按钮单击或其他事件）

在cross_mark功能中添加以下内容：

def cross_mark(blk):
    tk.Button(blk, background='orange red', border=4, text='X', font='30').grid(row=0, column=0, columnspan=1, rowspan=1, sticky='nsew')
    mw.update_idletasks()
    mw.after(1000, comp_mark(blk))