nodejs中的“where in”MySQL查询

Question

我需要使用“WHERE IN”进行MySQL查询。 这是我的查询：

var myQuery = 'SELECT uid FROM ' +tableName+ ' where Gender IN (' + Info.Gender.join() + ')';

如果我打印

Info.Gender

它将是 ['Male', 'Female']，作为字符串。 但当查询完成后，它会说

SELECT uid FROM appUsers where Gender IN (Male, Female)

但应该是：

SELECT uid FROM appUsers where Gender IN ('Male', 'Female')

这意味着它将 Female 不作为字符串。

有什么想法吗？

Answer 1

您应该使用查询转义（前提是您使用

node-mysql

）：

var myQuery = 'SELECT uid FROM ?? where Gender IN (?)';
connection.query(myQuery, [ tableName, Info.Gender ], ...);

Answer 2

您的查询中需要单引号：

var myQuery = "SELECT uid FROM " +tableName+ " where Gender IN ('" + Info.Gender.join("','") + "')";

Answer 3

您也可以将

Info.Gender

作为数组传递：

var myQuery = `SELECT uid FROM users where Gender IN (?)`
var arrayData = ['Male', 'Female']
connection.query(myQuery, [arrayData])